A total charge of –6.50 µC is uniformly distributed within a sphere that has a radius of 0.150 m. What is the magnitude and dire
1 answer:
Answer:
A) 2.89 × 105 N/C, radially inward
Explanation:
The magnitude of the electric field generated by a charged sphere is given by the following formula:
( 1 )
k: Coulomb's constant = 8.98*10^9 Nm^2/C^2
Q: charge of the sphere = -6.50*10^-6 C
r: distance from the center of the sphere to the point in which E is calculated
r = 0.150m + 0.300m = 0.450 m
You replace the values of Q and r in the equation (1):
The electric field points radially inward because the charge is negative.
hence, the answer is:
A) 2.89 × 105 N/C, radially inward
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Answer:
See bolded below.
Explanation:
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Here is how this will play out. Particle 1, with great velocity, will hit particle 2, which would mean that Particle 2 has less velocity than Particle 1. Now after the collision, energy is transferred to Particle 2, and while Particle 1 has now stopped in it's tracks, Particle 2 - with more energy than before - will continue as long as it has to before friction eventually brings it to a stop.
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From this we can conclude that Vf, from the picture below, must have less energy than V1, but more energy than V2 - and vice versa.
