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laila [671]
3 years ago
8

If the accuracy in measuring the position of a particle increases, what happens to the accuracy in measuring its velocity? - The

accuracy in measuring its velocity becomes uncertain.
- The accuracy in measuring its velocity remains the same.
- The accuracy in measuring its velocity also increases.
- The accuracy in measuring its velocity decreases.
Physics
1 answer:
timofeeve [1]3 years ago
5 0

Answer:

- The accuracy in measuring its velocity decreases.

Explanation:

This can be explained by Heisenberg's uncertainty principle which states that the position and velocity of a particle can be determined together exactly in reality.

This principle, unlike Newtonian mechanics deal with particles at microscopic level like that of an electron where if the accuracy in measurement of particle's position increases there will be  decreased accuracy in measurement of velocity of that particle.

There will be an uncertainty in accuracy in the measurement of particle's position and its velocity.

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</span><span>(3 kg)(9.8 m/s^2) = -k(-0.38 m)
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7 0
3 years ago
Sound exits a diffraction horn loudspeaker through a rectangular opening like a small doorway. Such a loudspeaker is mounted out
blondinia [14]

Answer:

\theta = 20.98 degree

Explanation:

As we know that the speed of the sound is given as

v = 332 + 0.6 t

now at t = 273 k = 0 degree

v = 332 m/s

so we have

a sin\theta = N\lambda

a sin\theta = N(\frac{v_1}{f})

now when temperature is changed to 313 K we have

t = 313 - 273 = 40 degree

now we have

v = 332 + (0.6)(40)

v_2 = 356 m/s

a sin\theta' = N(\frac{v_2}{f})

now from two equations we have

\frac{sin19.5}{sin\theta} = \frac{332}{356}

so we have

sin\theta = 0.358

\theta = 20.98 degree

7 0
3 years ago
11–8 Consider a heavy car submerged in water in a lake with a flat bottom. The driver’s side door of the car is 1.1 m high and 0
Greeley [361]

Answer:

Explanation:

position of centre of mass of door from surface of water

= 10 + 1.1 / 2

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10 ⁵ + hdg

= 10⁵ + 10.55 x 1000 x 9.8

= 2.0339 x 10⁵ Pa

the net force acting on the door (normal to its surface)

= pressure at the centre x area of the door

= .9 x 1.1 x 2.0339 x 10⁵

= 2.01356 x 10⁵ N

pressure centre will be at 10.55 m below the surface.

When the car is filled with air or  it is filled with water , in both the cases pressure centre will lie at the centre of the car .

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3 years ago
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SOVA2 [1]

Answer:

3 m/s

Explanation:

The slope is distance divided by time, also known as 'speed'.

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