Answer:
Look at the picture.
Explanation:
On stage one binding of a substrate occurs (and also the geometry of active site may change) and water comes to the site. On stage two the hydrolisis takes place and on stage 3 products deabsorb from the enzyme.
<u>Answer:</u> The amount of formed is 469.8 grams.
<u>Explanation:</u>
To calculate the number of moles, we use the equation:
......(1)
Given mass of phosphine = 225 g
Molar mass of phosphine = 34 g/mol
Putting values in equation 1, we get:
The given chemical reaction follows:
Assuming that oxygen gas is present in excess, it is considered as an excess reagent.
Phosphine is considered as a limiting reagent because it limits the formation of product.
By Stoichiometry of the reaction:
4 moles of phosphine produces 1 mole of
So, 6.62 moles of phosphine will produce = of
Now, calculating the mass of by using equation 1:
Molar mass of = 283.9 g/mol
Moles of = 1.655 moles
Putting values in equation 1, we get:
Hence, the amount of formed is 469.8 grams.