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Phoenix [80]
3 years ago
14

A student has a 1g sample of each of the following compounds: NaCl, KBr, and KCL Which of the following lists the samples in ord

er of increasing number of moles in the sample?
Chemistry
1 answer:
krek1111 [17]3 years ago
4 0

Given :

A student has a 1 g sample of each of the following compounds: NaCl, KBr, and KCl.

To Find :

The samples in order of increasing number of moles in the sample.

Solution :

Molecular mass of NaCl, KBr, and KCl is 58.5 g/mol , 119 g/mol and

74.5 g/mol respectively .

Moles of NaCl , n_1=\dfrac{1}{58.5}=0.017\ mol.

Moles of KBr , n_2=\dfrac{1}{119}=0.008\ mol.

Moles of KCl , n_2=\dfrac{1}{74.5}=0.013\ mol.

The order of moles in increasing order is :

KBr , KCl and NaCl .

Hence , this is the required solution .

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A chemistry student needs to standardize a fresh solution of sodium hydroxide. She carefully weighs out 385.mg of oxalic acid H2
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Answer:

The molarity of the sodium hydroxide solution is 0.0692 M

Explanation:

<u>Step 1: </u>Data given

Mass of H2C2O4 = 385 mg = 0.385 grams

volume = 250 mL = 0.250 L

Volume of NaOH = 123.7 mL = 0.1237 L

Molar mass H2C2O4 = 90.03 g/mol

<u>Step 2</u>: The balanced equation

2NaOH + H2C2O4 → Na2C2O4 + 2H2O

<u>Step 3:</u> Calculate moles H2C2O4

Moles H2C2O4 = mass H2C2O4 / molar mass H2C2O4

Moles H2C2O4 = 0.385 grams / 90.03 g/mol

Moles H2C2O4 = 0.00428 moles

<u>Step 4: </u>Calculate molarity of H2C2O4

Molarity H2C2O4 = moles / volume

Molarity H2C2O4 = 0.00428 moles / 0.250 L

Molarity H2C2O4 = 0.01712 M

<u>Step 5:</u> Calculate molarity of NaOH

2*Ca*Va = n*Cb*Vb

⇒ with Ca = Molarity of H2C2O4 = 0.01712 M

⇒ Va = volume of H2C2O4 = 0.250 L

⇒Cb = molarity of NaOH = TO BE DETERMINED

⇒ Vb = volume of NaOH = 0.1237 L

Cb = (2*0.01712*0.250)/0.1237

Cb = 0.0691 M

The molarity of the sodium hydroxide solution is 0.0692 M

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Answer:

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