<h2>1.15 moles</h2>
Explanation:
The ideal gas law is written as 
where
are the pressure, volume and temperature,
is the number of moles of gas; and
is the ideal gas constant. It is the same for all gases.
Given,





Since,
So,the number of moles is 
Answer:
9.2
Explanation:
M = mol of solute/L of solution
L/325 mL x 1000 mL/L = 0.325 L
3.0/0.325 = 9.2
*2 sig figs*
The average rate of formation of O2 is 4.225 × 10-4 M min-1
<h3>What is the equation of the reaction?</h3>
The equation of the reaction is given below:
From the equation of the reaction, 2 moles of Ibuprofen pentoxide decomposes to produce 1 mole of oxygen.
<h3>What is the average rate of formation of 02?</h3>
Rate of reaction is given as:
- Moles of product formed/moles of reactants used up/ time
- The ratio of mole of dinitrogen pentoxide decomposed to moles of oxygen produced is 2:1
Rate of disappearance of N2O5 = 8.45×10-4 M min-1.
Therefore, average rate of formation of O2 = 1/2 × 8.45×10-4 M min-1
Average rate of formation of O2 = 4.225 × 10-4 M min-1
Therefore, the average rate of formation of O2 is 4.225 × 10-4 M min-1
Learn more about rate of reaction at: brainly.com/question/24795637
Cesium.
Groups are the vertical columns that run up and down while periods are the horizontal rows. So to find the answer to this, go to the first column (Group 1) and find the sixth period (row 6) which will land you on Cesium, element 55.
Hope this helps!
Answer:
8moles
Explanation:
We are given the mass of ammonia to be 136g
Ammonia = NH₃
Let us find the number of moles in ammonia;
Number of moles =
Molar mass of ammonia = 14 + 3(1) = 17g/mol
so;
Number of moles =
= 8moles