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goblinko [34]
3 years ago
10

A long cylindrical insulator has a uniform charge density of 1.54 µc/m3 and a radius of 6cm what is the electric field inside th

e insulator at a distance of 2 cm

Physics
1 answer:
Lubov Fominskaja [6]3 years ago
4 0
Plug given values in SI units to get electric field.

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Can all rocks be weathered and eroded?how do you know?
skelet666 [1.2K]

Answer:yes

Explanation: Rock can be weathered by ice, acids, animals, temp and etc because the breaking down or dissolving of rock and minerals on the earths surface.

rocks can be eroded by wind, water, ice and, gravity be cause of an action, and friction.

(I think going off of what i learned.)

8 0
3 years ago
Read 2 more answers
What magnification is best for the observation of most tissue slides? Explain why this has proved to be true?
Komok [63]

Answer:

The 10X objective is use for the identification of actual size of histology tissues and 4X magnification is best for observation of most tissues slides

Explanation:

4X magnification is best for observation of most tissues slides because it has an objective lens that have lower power and have great high field overview which make it very easier to locate specimens on the slide. It is use to get the overview of histology slides. It is use to showcase more detailed observations about histology.

The 40X objective is use majorly to identify tissue , to observe the finer details and study tissue organization on the histology slide.

7 0
4 years ago
The word “virtual” refers to something that exists in effect but not in actual fact. How does this definition relate to the virt
atroni [7]
Because you see yourself the opposite way in a mirror. So yes your “seeing” yourself but not how everyone else sees you.
8 0
3 years ago
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A room has a wall with an R value of 18 F sq.ft. hr/BTU. The room is 15 feet long and 11 feet wide with walls that are 9 ft high
seropon [69]

Answer:

The heat transferred through the wall that day is  13728 BTUs

Explanation:

Here, we have the area of the wall given as

Area of wall = 2 × Length × Height + 2 × Width × Height

Length = 15 feet

Width = 11 Feet and

Height = 9 feet

Therefore, the area = 2×15×9 + 2×11×9 = 468 ft²

Temperature difference is given by

Average outside temperature - Wall temperature = 40 - 18 = 22 °F

Therefore the heat transferred through the wall that day (24 hours) at 18 sq.ft. hr/BTU is given by;

468 × 22 × 24/18 = 13728 = 13728 BTUs.

5 0
3 years ago
It opens or close the circuit​
gayaneshka [121]

Answer:

The person above me is right i had a test a couple of days ago and thats kinda what u put and got it right!

3 0
2 years ago
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