All categories

4 years ago

Whats A Controlled Experiment? Whats A Controlled Experiment? Like what the definition is please!

Physics

1 answer:

frozen [14]4 years ago

3 0

A controlled experiment is when scientests go throw thests to make an experiment

You might be interested in

Where is cloud data stored?

Annette [7]

Answer: i think its local drive

Explanation:

5 0

3 years ago

Read 2 more answers

A bullet of mass 0.016 kg traveling horizontally at a speed of 280 m/s embeds itself in a block of mass 3 kg that is sitting at

ivanzaharov [21]

(a) 1.49 m/s

The conservation of momentum states that the total initial momentum is equal to the total final momentum:

$p_i = p_f\\m u_b + M u_B = (m+M)v$

where

m = 0.016 kg is the mass of the bullet

$u_b = 280 m/s$ is the initial velocity of the bullet

M = 3 kg is the mass of the block

$u_B = 0$ is the initial velocity of the block

v = ? is the final velocity of the block and the bullet

Solving the equation for v, we find

$v=\frac{m u_b}{m+M}=\frac{(0.016 kg)(280 m/s)}{0.016 kg+3 kg}=1.49 m/s$

(b) Before: 627.2 J, after: 3.3 J

The initial kinetic energy is (it is just the one of the bullet, since the block is at rest):

$K_i = \frac{1}{2}mu_b^2 = \frac{1}{2}(0.016 kg)(280 m/s)^2=627.2 J$

The final kinetic energy is the kinetic energy of the bullet+block system after the collision:

$K_f = \frac{1}{2}(m+M)v^2=\frac{1}{2}(0.016 kg+3 kg)(1.49 m/s)^2=3.3 J$

(c) The Energy Principle isn't valid for an inelastic collision.

In fact, during an inelastic collision, the total momentum of the system is conserved, while the total kinetic energy is not: this means that part of the kinetic energy of the system is losted in the collision. The principle of conservation of energy, however, is still valid: in fact, the energy has not been simply lost, but it has been converted into other forms of energy (thermal energy).

4 0

4 years ago

A kid at the junior high cafeteria wants to propel an empty milk carton along a lunch table by hitting it with a 3.0g spit ball.

Natasha_Volkova [10]

Answer:

4.3 m/s

Explanation:

Using conservation of momentum, assume that the collision is elastic and that the 3.0 g ball stuck with the carton

3.0 g = 3 / 1000 = 0.003 kg = m₁

40 g = 40 / 1000 = 0.04 kg = m₂, u₂ = 0 since the body is stationary and v = 0.3m/s

m₁u₁ + m₂u₂ = v ( m₁ + m₂)

0.003 u₁ = 0.30 ( 0.003 + 0.04) = 0.0129

u₁ = 0.0129 / 0.003 = 4.3 m/s

5 0

3 years ago

Can someone please help on this one?

zhuklara [117]

Please READ Newton's first law of motion, and you'll see how nicely it explains that fact.

8 0

4 years ago

a crane convert 1000oule of energy in one second if it can do any work in one minute calculate the work done

dedylja [7]

A 1000J or 1kJ of energy in 1 second implies that in 1 minute there will be 60kJ of energy converted.

Work is the defined as energy consumed thought time.

$W=\dfrac{E}{t}$

In our case,

$W=\dfrac{60\mathrm{kJ}}{60\mathrm{s}}=1\cdot10^3\dfrac{\mathrm{J}}{\mathrm{s}}=\boxed{10^3\mathrm{W}}$

Hope this helps!

8 0

4 years ago