Question

An electric motor and a single-fixed pulley work together to lift a 500 kg crate 50.0 m. How much work was done?

Answer 1

Answer : Work done, W = 245,000 J

Explanation :

It is given that,

Mass of the system, m = 500 kg

Distance, d = 50 m

According to the definition of work done, $W=force\times displacement$

So, work done to lift the system of electric motor and a pulley is :

$W=mg\times h$

$W=500\ kg\times 9.8\ m/s^2\times 50\ m$

$W=245,000\ J$

Hence, this is the required solution.

Answer 2

Answer: The work done is 245000 J.  

Explanation:  

The formula for the force due to the weight of the object is as follows;

$F=mg$

Here, m is the mass of the object and g is the acceleration due to gravity.

Put m=500 kg and g=9.8 meter per second.

$F=(500)(9.8)$

$F=4900 N$

The formula for the work done is as follows;

$W=Fs$

Here, F is the force and s is the displacement.

Put F=4900 N and s=50.0 m.

$W=(4900)(50)$

$W=245000 J$

Therefore, the work done is 245000 J.