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lana66690 [7]
4 years ago
8

An electric motor and a single-fixed pulley work together to lift a 500 kg crate 50.0 m. How much work was done?

Physics
2 answers:
tamaranim1 [39]4 years ago
8 0

Answer : Work done, W = 245,000 J

Explanation :

It is given that,

Mass of the system, m = 500 kg

Distance, d = 50 m

According to the definition of work done, W=force\times displacement

So, work done to lift the system of electric motor and a pulley is :

W=mg\times h

W=500\ kg\times 9.8\ m/s^2\times 50\ m

W=245,000\ J

Hence, this is the required solution.

tester [92]4 years ago
3 0

Answer: The work done is 245000 J.  

Explanation:  

The formula for the force due to the weight of the object is as follows;

F=mg

Here, m is the mass of the object and g is the acceleration due to gravity.

Put m=500 kg and g=9.8 meter per second.

F=(500)(9.8)

F=4900 N

The formula for the work done is as follows;

W=Fs

Here, F is the force and s is the displacement.

Put F=4900 N and s=50.0 m.

W=(4900)(50)

W=245000 J

Therefore, the work done is 245000 J.

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A 23 g bullet traveling at 230 m/s penetrates a 2.0 kg block of wood and emerges cleanly at 170 m/s. If the block is stationary
Ann [662]

The distance traveled by the wood after the bullet emerges is 0.16 m.

The given parameters;

  • <em>mass of the bullet, m = 23 g = 0.023 g</em>
  • <em>speed of the bullet, u = 230 m/s</em>
  • <em>mass of the wood, m = 2 kg</em>
  • <em>final speed of the bullet, v = 170 m/s</em>
  • <em>coefficient of friction, μ = 0.15</em>

The final velocity of the wood after the bullet hits is calculated as follows;

m_1u_1 + m_2 u_2 = m_1v_1 + m_2v_2\\\\0.023(230) + 2(0) = 0.023(170) + 2v_2\\\\5.29 = 3.91 + 2v_2\\\\2v_2 = 1.38\\\\v_2 = \frac{1.38}{2} = 0.69 \ m/s

The acceleration of the wood is calculated as follows;

\mu = \frac{a}{g} \\\\a = \mu g\\\\a = 0.15 \times 9.8\\\\a = 1.47 \ m/s^2

The distance traveled by the wood after the bullet emerges is calculated as follows;

v^2 = v_0^2 + 2as\\\\v^2 = 0 + 2as\\\\v^2 = 2as\\\\s = \frac{v^2}{2a} \\\\s = \frac{(0.69)^2}{2(1.47)} \\\\s = 0.16 \ m

Thus, the distance traveled by the wood after the bullet emerges is 0.16 m.

Learn more here:brainly.com/question/15244782

7 0
3 years ago
An unknown substance has a mass of 0.125 kg and an initial temperature of 95.0°C. The substance is then dropped into a calorimet
mr Goodwill [35]

Answer:

c = 1163.34 J/kg.°C

Explanation:

Specific heat capacity:

"Specific heat capacity is the amount of heat energy required to raise the temperature of a substance per unit of mass. The specific heat capacity of a material is a physical property."

Use this equation:

mcΔT = ( mw c + mAl cAl )  ΔT'

Rearranging the equation to find the specific heat (c) you get this:

c = (( mw c + mAl cAl )  ΔT') / (mΔT)

c = (( 0.285 (4186) + (0.15)(900)) (32 -25.1)) / ((0.125) (95 - 32))

c = 1163.34 J/kg.°C

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4 years ago
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What is the displacement of the object from 2 seconds to 6 seconds?
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the answer would be 4

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3 years ago
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If you're studying the science of sound, you're studying____?
timurjin [86]
The study of sound is called sonics and the study of sound waves are acoustics
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A bell is ringing inside of a sealed glass jar that is connected to a vacuum pump. Initially, the jar is filled with air. What d
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Answer:

See Explanation

Explanation:

Sound is a mechanical wave. A mechanical wave requires a material medium for propagation. This means that sound waves must be carried in air. If there are no air molecules, sound waves can not travel.

When air is gradually removed from the jar by the pump, the sound intensity from the bell gradually decreases owing to the fact that air which is the medium through which sound waves are propagated is gradually being removed from the jar.

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