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MakcuM [25]
2 years ago
9

After a laser beam passes through two thin parallel slits, the first completely dark fringes occur at 19.0 with the original dir

ection of the beam, as viewed on a screen far from the slits. (a) What is the ratio of the distance between the slits to the wavelength of the light illuminating the slits
Physics
1 answer:
Katarina [22]2 years ago
8 0

Answer:

$\frac{d}{\lambda} = 1.54$

Explanation:

Given :

The first dark fringe is for m = 0

$\theta_1 = \pm 19^\circ$

Now we know for a double slit experiments , the position of the dark fringes is give by :

$d \sin \theta=\left(m+\frac{1}{2}\right) \lambda$

The ratio of distance between the two slits, d to the light's wavelength that illuminates the slits, λ :

$d \sin \theta=\left(\frac{1}{2}\right) \lambda$     (since, m = 0)

$d \sin \theta=\frac{\lambda}{2}$

$\frac{d}{\lambda} = \frac{1}{2 \sin \theta}$

$\frac{d}{\lambda} = \frac{1}{2 \sin 19^\circ}$

$\frac{d}{\lambda} = 1.54$

Therefore, the ratio is $\frac{1}{1.54}$  or 1 : 1.54

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The presence of foreign pottery in a well-dated Egyptian context shows that this type of pottery cannot be more recent than thos
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TERMINUS ANTE QUEM

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Example, a pottery dating to the 4th century AD found on a surface would give that pottery with a terminus ante quem of the 4thcentury AD.

This type of cross dating can either be TERMINUS ANTE QUEM OR TERMINUS POST QUEM.

3 0
2 years ago
On the Apollo 14 mission to the moon, astronaut Alan Shepard hit a golf ball with a 6 iron. The acceleration due to gravity on t
castortr0y [4]

Answer:

4.86 seconds

Explanation:

Velocity of projection, u = 14 m/s

angle of projection, θ = 20°

Formula for the time of flight

T=\frac{2uSin\theta }{g}

For earth

Te = (2 x 14 x Sin 20) / 9.8

Te = 0.98 s

For moon

g' = g/6 = 1.64 m/s^2

Tm = ( 2 x 14 x Sin 20) / 1.64

Tm = 5.84 seconds

Tm - Te = 5.84 - 0.98 = 4.86 s

So, it takes 4.86 s more time of flight on moon than the earth.  

5 0
3 years ago
Spaceship 1 and spaceship 2 have equal masses of 150kg. Spaceship 1 has the speed of 0 m/s and spaceship 2 has a speed of 6 m/s.
Anna11 [10]

Answer:

3 m/s

Explanation:

The computation of speed is shown below:-

We will compute the equation by using the law of conservation of momentum; also, the total momentum prior and following the collision must be conserved. Therefore we can write the equation is the following manner:-

m_1 u_1 + m_2 u_2 = (m_1 +m_2)v

where the symbols represent

150 kg is the mass of spaceship 1  = m1

150 kg is the mass of spaceship 2  = m2

0 m/s is the initial velocity of spaceship 1  = u1

6 m/s is the initial velocity of spaceship 2 = u2

and v is the velocity of the 2 ships so that they can collide and combined together

For v we will get the following equation to reach the speed

v=\frac{m_1 u_1 + m_2 u_2}{m_1+m_2}

=\frac{0+(150)(6)}{150+150}

=3 m/s

5 0
3 years ago
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