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Tanya [424]
2 years ago
13

Why is it better to drive a large SUV in icy conditions with chains on the tires, instead of a small car with old tires? Explain

your answer using the terms: Force of Friction, Normal Force, Coefficient of friction, mass, rough, and smooth.
Plisss I need help
Physics
1 answer:
Step2247 [10]2 years ago
4 0

Answer:

It is better to drive a large SUV in stead of a smaller car in icy conditions, because the large SUV contains enough friction of force to drive in the snow on the ground. The mass of the car also plays a huge effect on this because then it does not slide off the road. The large tires on the big SUV make you ride smoothly through the snow and ice. With driving a smaller car though, the old tires have already been through a lot of driving, so this makes driving the car rough on the road. This also makes it so there is not a normal force in the wheels, so this means the car does not go at its normal speed, and this could cause an accident, or the rough tires could cause a fire when driving.

Trust me on this. I am 17, and I drive a Nissan Armada as my first car. Life changing. Happy Holidays!

Explanation:

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A stone is catapulted at time t = 0, with an initial velocity of magnitude 19.9 m/s and at an angle of 39.9° above the horizonta
larisa [96]

Answer:

Part a)

x = 15.76 m

Part b)

y = 7.94 m

Part c)

x = 26.16 m

Part d)

y = 7.49 m

Part e)

x = 83.23 m

Part f)

y = -75.6 m

Explanation:

As we know that catapult is projected with speed 19.9 m/s

so here we have

v_x = 19.9 cos39.9

v_x = 15.3 m/s

similarly we have

v_y = 19.9 sin39.9

v_y = 12.76 m/s

Part a)

Horizontal displacement in 1.03 s

x = v_x t

x = (15.3)(1.03)

x = 15.76 m

Part b)

Vertical direction we have

y = v_y t - \frac{1]{2}gt^2

y = (12.76)(1.03) - 4.9(1.03)^2

y = 7.94 m

Part c)

Horizontal displacement in 1.71 s

x = v_x t

x = (15.3)(1.71)

x = 26.16 m

Part d)

Vertical direction we have

y = v_y t - \frac{1]{2}gt^2

y = (12.76)(1.71) - 4.9(1.71)^2

y = 7.49 m

Part e)

Horizontal displacement in 5.44 s

x = v_x t

x = (15.3)(5.44)

x = 83.23 m

Part f)

Vertical direction we have

y = v_y t - \frac{1]{2}gt^2

y = (12.76)(5.44) - 4.9(5.44)^2

y = -75.6 m

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What allows the bimetallic coil to turn on or off a heating or cooling system? The two metals contract the same amount. The ther
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Answer:

The two metals expand differently.

Explanation:

The bimetallic strip has two metal strips positioned like a bridge, these strips connect the electrical circuit to the heating system. When these strips are linear or "down" they allow the electricity to move through the circuit to the heating system to turn the heat on. When the strips are "up" the disconnect the electricity flow, thus turning the heating system off, thus the room becomes cool/cold.

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Answer:

(d) not enough info

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