Nickel metal will react spontaneously with the aqueous lead solution [Pb2+(aq)].
Oxidation is a chemical reaction involving the loss of electrons. In the reactivity series of metals, chromium, barium, and lithium are more reactive or more easily oxidized than nickel.
In the given problem, because nickel is in its elemental (solid metal) form, for it to react with the solution, it will have to be converted into its cationic form (which is positively-charged) by losing electrons. However, if the solution that nickel is reacted with is more easily oxidized compared to nickel, then the reaction will not be spontaneous because nickel is stable in this case.
On the other hand, if nickel is immersed in a solution of a metal which is more stable than it is, such as lead, nickel will be oxidized and lose its electrons to the more stable metal. The more stable metal in solution will accept the lost electrons of nickel and form a solid deposit, while nickel will be in its ionic form in solution.
Below is a reaction between nickel metal and aqueous lead nitrate solution.
The molecular geometry is square planar.
According to the Valence Shell Electron Pair Repulsion theory (VSEPR), the shape of a molecule is determined by the number of valence electrons surrounding the outermost shell of the central atom in the molecule.
In this case, the expected geometry based on VSEPR theory is octahedral. However, the lone pairs on opposite sides of the four single bonds leads to a square planar molecular geometry.
Learn more; brainly.com/question/24396703
The pH of a solution which is 0.023 m in weak base and 0 037 m in the conjugate weak acid whose Ka= 7.1 × 10⁻⁶ is 4.93.
pH determines the amount of hydrogen and hydroxide ions in a solution. It is the negative logarithm of hydrogen ion concentration.
Given,
Ka= 7.1 × 10⁻⁶
Weak base = 0.023M
Acid = 0.037M
Using base dissociation constant, Ka we can calculate pKa by:
pKa = -log [Ka]
pKa = -log [7.1 × 10⁻⁶]
pKa = 5.15
A weak base and its conjugate acid are present in equal proportions in buffer solution. Using the Henderson-Hasselbalch equation, we can find out the pH of a buffer solution that constitutes a weak base and its conjugate acid.
Using Henderson-Hasselbalch equation,
pH = pKa + log [Weak base / acid]
pH = 5.15 + log [0.023 / 0.037]
pH = 5.15 + log[0.6]
pH = 5.15 - 0.22
pH = 4.93
Therefore, the pH of the solution is 4.93.
Learn more about pH here, brainly.com/question/22390063
#SPJ4
How many moles of oxygen atoms are present in 5
moles of Mg3(PO4)2
All you have to do is to create
a ratio between the molecule and the oxygen atom.
5 moles of Mg3(PO4)2 (4x2 moles
O/1 mole Mg3(PO4)2) = 40 moles of oxygen