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Zina [86]
3 years ago
13

1.00-degree increase on the Celsius scale is equivalent to a 1.80-degree increase on the Fahrenheit scale. The temperature of a

fluid increases by 48.0°C. What is this increase in degrees Fahrenheit? 49.8°F 48.0°F 26.7°F 86.4°F
Chemistry
1 answer:
castortr0y [4]3 years ago
6 0
48.0°C×1.80 = 86.4°F
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A particular uranium alloy has a density of 18.75 g/cm3.
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3 years ago
The atomic mass is the sum of the number of ________ and ________ in the nucleus of an atom. Choose two answers from the options
iVinArrow [24]

Answer :

The atomic mass is the sum of the number of protons and neutrons in the nucleus of an atom.

Explanation :

Atomic number : it is defined as the number of protons or number of electrons.

Atomic number = number of protons = number of electrons

Mass number or atomic mass : It is defined as the sum of the number of protons and the number of neutrons.

Mass number or atomic mass = Number of protons + Number of neutrons

For example :

Number of protons in carbon = 6

Number of neutrons in carbon = 6

Mass number or atomic mass = Number of protons + Number of neutrons

Mass number or atomic mass = 6 + 6

Mass number or atomic mass = 12

Thus, the atomic mass is the sum of the number of protons and neutrons in the nucleus of an atom.

3 0
3 years ago
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OT protons (d) (a) and (b)
insens350 [35]
<h2>b is the correct answer</h2>

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6 0
3 years ago
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Why does the sun appear to move from east to west across the sky? A. Due to Earth's revolution B. Due to Earth's rotation C. Due
yarga [219]

B. Due to Earth's rotation

7 0
3 years ago
What is the percent yield in a reaction between 42.6 g O2 and 49.2 g Al if 72.4 g of Al2O3 is produced?
pashok25 [27]

Answer:

229%

Explanation:

The equation of the reaction is;

4Al(s) + 3O2(g) ----> 2Al2O3(s)

We must first determine the limiting reactant;

Number of moles of Al2O3 produced = mass/molar mass = 72.4g/101.96 g/mol = 0.71 moles

For Al

Number of moles reacted = mass/molar mass = 49.2g/27 g/mol = 1.8 moles

If 4 moles of Al yields 0.71 moles of Al2O3

1.8 moles of Al will yield 1.8 × 0.71/4 = 0.32 moles of Al2O3

For O2

Number of moles reacted = mass/molar mass = 42.6g/32g/mol = 1.33 moles

If 3 moles of O2 yields 0.71 moles of Al2O3

1.33 moles of O2 will yield 1.33 × 0.71/3 = 0.31 moles of Al2O3

Oxygen is the limiting reactant.

% yield = actual yield/ theoretical yield × 100/1

% yield = 0.71 moles/0.31 moles × 100

% yield = 229%

4 0
3 years ago
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