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faltersainse [42]
4 years ago
11

What are some circumstances under which the coase theorem fails to apply?

Chemistry
1 answer:
Sloan [31]4 years ago
5 0

<u>Circumstance under which the Coase theorem fails;</u>

This theorem is not suited for practical applications because the initial allocation of property rights may affect the final result of the negotiations.

<u>Explanation:</u>

  • The Coase theorem was developed by an economist named Ronaldo Coase.
  • This theorem was introduced to resolve the issues involved during the price distribution in property rights.
  • Also, it states that the price of a property can be bargained between the two individuals to get a positive result.
  • But this theorem is not applicable for all situations, as the people who have the right to own his property expect to sell it at a higher rate than the market value.
  • This will leads to internal conflicts between the seller and the buyer and it affects the final price of that property.
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2 years ago
How many grams of F− must be added to a cylindrical water reservoir having a diameter of 2.02 × 102 m and a depth of 87.32 m?
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Complete Question:

To aid in the prevention of tooth decay, it is recommended that drinking water contain 0.800 ppm fluoride. How many grams of F− must be added to a cylindrical water reservoir having a diameter of 2.02 × 102 m and a depth of 87.32 m?

Answer:

2.23x10⁶ g

Explanation:

The concentration of the fluoride (F⁻) must be 0.800 ppm, which is 0.800 parts per million, so the water must have 0.800 g of F⁻/ 1000000 g of the solution. The density of the water at room temperature is 997 kg/m³ = 997x10³ g/m³. So, the concentration of the fluoride will be:

0.800 g of F⁻/ 1000000 g of the solution * 997x10³ g/m³

0.7976 g/m³

The volume of the reservoir is the volume of the cylinder: area of the base * depth. The base is a circumference, which has an area:

A = πR², where R is the radius = 1.01x10² m (half of the diameter)

A = π*(1.01x10²)²

A = 32047 m²

The volume is then:

V = 32047 * 87.32

V = 2.7983x10⁶ m³

The mass of the F⁻ is the concentration multiplied by the volume:

m = 0.7976 * 2.7983x10⁶

m = 2.23x10⁶ g

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