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frutty [35]
3 years ago
15

The percentage yield of the following reaction is 85 %. 2 Al, +31--> 2 AICI. How many grams of AICI, will be actually obtaine

d from 1008 aluminium metal
Chemistry
1 answer:
Readme [11.4K]3 years ago
6 0

Answer:

Assuming the product is AlCl3

Assuming its 1008 g of metalic Al

It will yeld 4234 g of aluminium chloride.

Explanation:

Al molar mass is 26.98 g/mol, so in 1008 g of Al there is 37.36 mols of Al

The stoichometry ratio between Al and AlCl3 is 1:1, so 37.36 mols of Al would form 37.36 mols of AlCl3 if the reaction were complete, but only 85% yelds, so 1008 g of Al makes up to 0.85x37.36 mols of AlCl3 (31.76 moles)

AlCl3 molar mas is 133.33 g/mol, so 31.76 moles has 4234 g

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Explanation:

Complete question

Dissolved hydrofluoric acid reacts with dissolved sodium hydroxide to form water and aqueous sodium fluoride. What is the net ionic equation

Equilibrium equation between the undissociated acid and the dissociated ions

HF(aq)⇌H+(aq)+F−(aq)

Sodium hydroxide will dissociate aqueous solution to produce sodium cations, Na+, and hydroxide anions, OH−

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The Final equation is  

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