Question

what is the temperature of an 11.2 L sample of carbon monoxide, CO, at 744 torr if it occupies 13.3L at 55 degrees Celsius and 744 torr?

Answer 1

Answer:

3 °C

Explanation:

The pressure is constant, so this looks like a case where we can use Charles’ Law:

$\frac{ V_{1} }{T_{1}} = \frac{V_{2} }{T_{2}}$  

Invert both sides of the equation.

$\frac{T_{1} }{V_{1}} = \frac{T_{2} }{V_{2}}$

Multiply both sides by V₂

$T_{2} = T_{1} \times \frac{V_{2} }{ V_{1} }$

V₁ = 13.3 L; T₁ = (55 + 273.15) K = 328.15 K

V₂ = 11.2 L; T₂ = ?

$T_{2} = \text{328.15 K} \times \frac{\text{11.2 L} }{\text{13.3 L}} = \text{276 K} = 3 ^{\circ}\text{C}$