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r-ruslan [8.4K]

3 years ago

6

The milky way is often considered to be an intermediately wound, barred spiral, which would be type ________ according to hubble

. the milky way is often considered to be an intermediately wound, barred spiral, which would be type ________ according to hubble.

1 answer:

lora16 [44]3 years ago

4 0

SBb type spiral. Its a type B because its not too tightly wound but its still too tight to be a type C

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Help please due tomorrow

Anni [7]

Hope this helps!!!!

6 0

3 years ago

If it takes 600 N to move a box 5 meters, how much work is done on the box?

Arada [10]

Answer:3000joules

Explanation: work=force×distance

Work=600×5

Work=3000joules

6 0

4 years ago

A force vector F1 points due east and has a magnitude of 200N. A second force F2 is added to F1. The resultant of the two vector

PilotLPTM [1.2K]

Answer:

The second vector $\vec{F_2}$ points due West with a magnitude of 600N

Explanation:

The original vector $\vec{F_1}$ points with a magnitude of 200N due east, the Resultant vector $\vec{R}$ points due west (that's how east/west direction can be interpreted, from east to west) with a magnitude of 400N. If we choose East as the positive direction and West as the negative one, we can write the following vectorial equation:

$\vec{F_1}+\vec{F_2}=\vec{R}\implies\vec{F_2}=\vec{R}-\vec{F_1}=-400N-200N=-600N$

With the negative sign signifying that the vector points west.

3 0

4 years ago

A clarinetist, setting out for a performance, grabs his 3.230 kg3.230 kg clarinet case (including the clarinet) from the top of

SpyIntel [72]

Answer:

- 0.5 m/s²

Explanation:

m = mass of the clarinet case = 3.230 kg

W = weight of the clarinet case in downward direction

a = vertical acceleration of the case

Weight of the clarinet case is given as

W = mg

W = 3.230 x 9.8

W = 31.654 N

F = Upward force applied = 30.10 N

Force equation for the motion of the case is given as

F - W = ma

30.10 - 31.654 = 3.230 a

a = - 0.5 m/s²

8 0

3 years ago

Block A, with a mass of 4 kg, is moving with a speed of 2 m/s while Block B, with a mass of 8.4 kg, is moving in the opposite di

dybincka [34]

Answer:

The center of mass move with the velocity of -3.487 m/s.

Explanation:

Given values of block A.

Mass of block A, (M1) = 4 kg

Speed of block A, (V1) = 2 m/s

Given values of block B.

Mass of block B, (M2) = 8.4 kg

Speed of block B, (V2) = -6.1 m/s

Below is the formula to find the velocity of center of mass.

$Velocity = \frac{M1V1 + M2V2}{M1 + M2} \\$

$= \frac{4 \times 2 + 8.4 \times (-6.1) }{4 + 8.4} \\$

$= \frac{- 43.24}{12.4}\\$

$= - 3.487 m/s$

7 0

3 years ago