Answer:
The object is dropped, we know the initial velocity is zero. Once the object has left contact with whatever held or threw it, the object is in free-fall. Under these circumstances, the motion is one-dimensional and has constant acceleration of magnitude g.
No so sure
Explanation:
Hope it helps
1. b
2. c
3. a
4. a
5. b
6. should be 2400? unless u put the wrong numbers, it is probably 240 then
Explanation:
Given
radius![r=2.63 m](https://tex.z-dn.net/?f=r%3D2.63%20m)
![N=0.526 rev/s](https://tex.z-dn.net/?f=N%3D0.526%20rev%2Fs%20)
![\omega =3.30 rad/s](https://tex.z-dn.net/?f=%5Comega%20%3D3.30%20rad%2Fs)
mass disc ![M=152 kg](https://tex.z-dn.net/?f=M%3D152%20kg)
mass of person ![m=51.7 kg](https://tex.z-dn.net/?f=m%3D51.7%20kg)
velocity of Person ![v=2.76 m/s](https://tex.z-dn.net/?f=v%3D2.76%20m%2Fs)
moment of inertia ![I=Mr^2](https://tex.z-dn.net/?f=I%3DMr%5E2)
![I=0.5\times 152\times 2.63^2=827.64 kg-m^2](https://tex.z-dn.net/?f=I%3D0.5%5Ctimes%20152%5Ctimes%202.63%5E2%3D827.64%20kg-m%5E2)
Initial angular momentum
![L_i=I\omega +mvr](https://tex.z-dn.net/?f=L_i%3DI%5Comega%20%2Bmvr)
![L_i=827.64\times 3.30+51.7\times 2.76\times 2.63](https://tex.z-dn.net/?f=L_i%3D827.64%5Ctimes%203.30%2B51.7%5Ctimes%202.76%5Ctimes%202.63)
![L_i=2731.212+375.27=3106.48 Js](https://tex.z-dn.net/?f=L_i%3D2731.212%2B375.27%3D3106.48%20Js)
Final Moment inertia
![I_f=0.5Mr^2+mr^2](https://tex.z-dn.net/?f=I_f%3D0.5Mr%5E2%2Bmr%5E2)
![I_f=(152\cdot 0.5+51.7)\cdot (2.63)^2=1185.243 kg-m^2](https://tex.z-dn.net/?f=I_f%3D%28152%5Ccdot%200.5%2B51.7%29%5Ccdot%20%282.63%29%5E2%3D1185.243%20kg-m%5E2)
final angular momentum
![L_f=I_f\omega _f](https://tex.z-dn.net/?f=L_f%3DI_f%5Comega%20_f)
Conserving angular momentum
![L_i=L_f](https://tex.z-dn.net/?f=L_i%3DL_f)
![3106.48=1408.97\times \omega _f](https://tex.z-dn.net/?f=3106.48%3D1408.97%5Ctimes%20%5Comega%20_f%20)
![\omega _f=2.62 rad/s](https://tex.z-dn.net/?f=%5Comega%20_f%3D2.62%20rad%2Fs)