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3 years ago

5 points

Physics

1 answer:

Tresset [83]3 years ago

8 0

Answer:

$\frac{{v}^{2} g}{2 }$

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If a car takes a banked curve at less than a given speed, friction is needed to keep it from sliding toward the inside of the cu

zubka84 [21]

Answer:

minimum speed is 15.35 m/s

frictional coefficient is 0.26

Explanation:

given data

radius = 84 m

angle = 16°

speed = 16 km/h = 4.43 m/s

to find out

minimum speed and minimum coefficient

solution

we will apply here formula for velocity that is

velocity² = radius × g × tanθ

v² = 84 × 9.8 × tan16

v² = 236.04

v = 15.35 m/s

and

we find first friction force here

friction force 1 = m v² /r

friction force 1 = m (15.35)² / 84 = 2.80 m

and

friction force 2 = m v² /r

friction force 2 = m (4.43)² / 84 = 0.245 m

so total friction force = f1 - f2

total friction force = 2.80 - 0.245 = 2.55 m

so frictional coefficient = friction force /g

frictional coefficient = 2.55 / 9.8

so frictional coefficient is 0.26

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3 years ago

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How do like charges affect one another

dybincka [34]

Because if you have o<span>bjects with like charge they will repel each other</span>

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3 years ago

Your personal hygiene is more important to avoid you becoming ill, more so than spreading germs.

ycow [4]

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A projectile is fired horizontally off the top of a cliff with an initial velocity of 43 m/s. It hits the ground 3.0 seconds lat

sattari [20]

Answer:

44.1 m

Explanation:

The vertical motion of the projectile is a free fall motion, so it is a uniform accelerated motion. This means that we can use the suvat equation:

$s=ut+\frac{1}{2}at^2$

where , taking downward as positive direction:

s is the vertical displacement

u = 0 is the initial vertical velocity of the projectile (it is fired horizontally)

t is the time

$a=g=9.8 m/s^2$ is the acceleration of gravity

We know that the projectile hits the ground at

t = 3.0 s

Therefore, by substituting this value into the equation, we find the vertical displacement of the projectile at that time, that is equal to the height of the cliff:

$s=0+\frac{1}{2}(9.8)(3)^2=44.1 m$

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4 years ago

A girl stands on a moving sidewalk (conveyor belt) that is moving to the right at a speed of 2 m/s relative to the ground. A dog

klasskru [66]

Answer:

Explanation:

Given

Speed of elevator is given by $v_{eg}=2\ m/s$

Dog is running towards the girl with velocity $v=8_{ds}$ w.r.t sidewalk

Therefore velocity of dog w.r.t ground

$v_{ds}=v_{dg}-v_{eg}$

$v_{dg}=v_{ds}+v_{eg}$

$v_{dg}=8+2=10\ m/s$

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3 years ago