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3 years ago

6

The compressor on an air conditioner draws 35.0 A when it starts up. If the start-up time is 0.59 s, how much charge passes a cr

oss-sectional area of the circuit in this time?

1 answer:

Elden [556K]3 years ago

6 0

Answer:

is a conditioner es 13.4

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If the resultant force acting on a 2.0 kg object is equal to (3.0î + 4.0ĵ) N, what is the change in kinetic energy as the object

12345 [234]

Answer:

ΔK = 24 joules.

Explanation:

Δ $K =$ Work done on the object

Work is equal to the dot product of force supplied and the displacement of the object.

$W = F$ * Δ $s$

Δ $s$ can be found by subtracting the vectors (7.0, -8.0) and (11.0, -5.0), which is written as Δ $s$ = (11.0 - 7.0, -5.0 - -8.0) which equals (4.0, 3.0).

This gives us

$W = < 3, 4 >$ * $< 4, 3 >$ = $(3*4)+(4*3)$ = $24$ J

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1 year ago

An object is dropped on Earth from a height of 15 m. What is the magnitude of the velocity of the object just as it hits the gro

ivolga24 [154]

Here, we know, according to 3rd Equation of Kinematics,
v² - u² = 2as

Here, u = 0 [ Free fall ]
a = 9.8 m/s² [ constant value for the Earth system ]
s = 15 m

Substitute their values,
v² - 0² = 2 * 9.8 * 15
v² = 294
v = √294
v = 17.15 m/s

In short, Your Answer would be Option D

Hope this helps!

8 0

3 years ago

Read 2 more answers

A row of seats is parallel to a stage at a distance of 90 m from it. At the center and front of the stage is a diffraction horn

Serggg [28]

Answer:

distance between seats = 2*11.10 = 22.20 m

Explanation:

seats row is parallel to a stage with a distance d = 90 m

doorway width = 0.070 m

speaker frequency = 4.00 * 10^4 Hz

Speed of sound = 343 m/s

tone will be heard at

$sin \theta = \frac{\lambda}{D}$

we know that $v =\lambda d$

so

$sin\theta = \frac{v}{dD}$

$= \frac{343}{4.00 * 10^4*0.070}$

$sin\theta = 0.1225$

$\theta = 7.036 degree$

$tan\theta =\frac{x}{d}$

[tex]x = d*tan\theta = 90*0.1234 = 11.10 m

distance between seats = 2*11.10 = 22.20 m

7 0

3 years ago

A 0.290 cm diameter plastic sphere, used in a static electricity demonstration, has a uniformly distributed 30.0 pC charge on it

mojhsa [17]

Answer:

Therefore,

The potential (in V) near its surface is 186.13 Volt.

Explanation:

Given:

Diameter of sphere,

d= 0.29 cm

$radius=\dfrac{d}{2}=\dfrac{0.29}{2}=0.145\ cm$

$r = 0.145\ cm = 0.145\times 10^{-2}\ m$

Charge ,

$Q = 30.0\ pC=30\times 10^{-12}$

To Find:

Electric potential , V = ?

Solution:

Electric Potential at point surface is given as,

$V=\dfrac{1}{4\pi\epsilon_{0}}\times \dfrac{Q}{r}$

Where,

V= Electric potential,

ε0 = permeability free space = 8.85 × 10–12 F/m

Q = Charge

r = Radius

Substituting the values we get

$V=\dfrac{1}{4\times 3.14\times 8.85\times 10^{-12}}\times \dfrac{30\times 10^{-12}}{0.145\times 10^{-2}}$

$V=\dfrac{30}{16.117\times 10^{-2}}=186.13\ Volt$

Therefore,

The potential (in V) near its surface is 186.13 Volt.

3 0

3 years ago

What is the definition of the product of force and distance applied to an force

amid [387]

Answer:

that is the definition of work

Explanation:

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3 years ago