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Dmitry [639]
4 years ago
10

a. (24 points) Describe the microstructure present in a 10110 steel after each step in each of the following heat treatments (no

te that i-iv are all individual heat treatments on different specimens, not a sequence of heat treatments on a single specimen; each will have a separate answer): i) Heat to 900 ºC, quench to 400 ºC and hold for 1000 sec. and then quench to 25 ºC. ii) Heat to 900 ºC, and then quench to 25 ºC. iii) Heat to 900 ºC, quench to 700 ºC and hold for 1 sec., quench to 600 ºC and hold for 1 sec, quench to 400 ºC and hold for 10 sec., quench to 300 ºC and hold for 100 sec, and then quench to 25 ºC. iv) Heat to 900 ºC, quench to 675 ºC and hold for 1 sec, quench to 300 ºC and hold for 1000 sec, and then quench to 25 ºC. b. (10 points) Describe the difference in final microstructures for 1080 and 1020 steels when cooled to room temperature at cooling rates of: i) 4 ºC/s ii) 25 ºC/s iii) 53 ºC/s iv) 120 ºC/s c. (6 points) Why is there a cementite start line for the 10110 steel but none for the 1050 steel?

Engineering
1 answer:
Mrac [35]4 years ago
6 0

Answer:

Explanation:

Please check the below file for the attached file

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The critical resolved shear stress for a metal is 39 MPa. Determine the maximum possible yield strength (in MPa) for a single cr
damaskus [11]

Answer:

78 MPa

Explanation:

Given that the critical resolved shear stress for a metal is 39 MPa, the maximum possible yield strength for a single crystal of this metal is twice the critical resolved shear stress for the metal. The maximum yield yield strength for a single crystal of this metal that is pulled in tension (\sigma_y) is given as:

\sigma_y=2*critical\ resolved\ shear\ stress(\tau_{css})\\\\\sigma_y=2*\tau_{css}\\\\\sigma_y=2*39\\\\\sigma_y=78\ MPa

4 0
3 years ago
A 2-kW pump is used to pump kerosene ( rho = 0. 820 kg/L) from a tank on the ground to a tank at a higher elevation. Both tanks
Alborosie

The maximum volume flow rate of kerosene is 8.3 L/s

<h3>What is the maximum volume flow rate?</h3>

In fluid dynamics, the maximum volume flow rate (Q) is the volume or amount of fluid flowing via a required cross-sectional area per unit time.

In fluid mechanics, using the following relation, we can determine the maximum volume flow rate of kerosene.

  • Power = mass flow rate(m) × specific work(w)   --- (1)
  • Specific work = acceleration due to gravity (g) × head (h)   ---- (2)
  • Mass flow rate (m) = density (ρ) × volume flow rate (Q) --- (3)

By combining the three equations together, we have:

The power gained through the fluid pump to be:

  • P = ρ × Q × g × h

Making Q the subject, we have:

\mathbf{Q = \dfrac{P}{\rho \times g \times h}}

where:

  • P = 2 kW = 2000 W
  • ρ = 0.820 kg/L
  • g = 9.8 m/s
  • h = 30 m

\mathbf{Q = \dfrac{2000 \ W }{820 \ kg/m^3 \times 9.8 m/s \times 30 \ m}}

Q  = 0.008296 m³/s

Q ≅ 8.3 L/s

Learn more about the maximum volume flow rate here:

brainly.com/question/19091787

8 0
2 years ago
If a vacuum gau ge reads 9.62 psi, it means that: a. the very highest column of mercury it could support would be 19.58 inches.
scZoUnD [109]

Answer:All of the above

Explanation:

9.62 psi means 497.49 mm of Hg pressure

for (a)19.58 inches is equals to 497.49 mm of Hg

(b)atmospheric pressure is 14.69 psi

vaccum gauge is 9.62psi

absolute pressure is=14.69-9.62=5.07

(c)vaccum means air is sucked and there is negative pressure so it tells about below atmospheric pressure.

thus all are correct

8 0
4 years ago
An experiment is performed to determine the boiling characteristics of a special coating applied to the exposed surface. Under s
Dmitry [639]

Answer:

hello your question incomplete attached below is the complete question and detailed solution

Answer : Csf = 0.0131

Explanation:

Attached below is the detailed solution

Given data :

ΔTe = 17.1⁰c calculated as ;Ts - Tsat = ( 117.1 - 100 )

Pe = 957.9 kg/m^3

Cp1e = 4217 j/kgk

<em>U</em>e = 279 * 10^-6 n. s / m^2

Pre = 1.76

hfg = 2.257 * 10^6 J/kg

Pv = 0.5955 kg/m^3

б = 0.0589 N/m

q" = 664 * 10^3 w/m^2 ( calculated )

Input these values into equation 1 as contained in the detailed solution

Csf = 0.0131

3 0
3 years ago
How much power is needed to operate a Carnot heat pump if the pump receives heat 10°C and delivers 50 kW of heat at 40°C? at A)
mariarad [96]

Answer:

Power needed to pump=4.79 KW.

Explanation:

Given that:T_{1}=283K,T_{2}=313K,Q_{H}=50KW

We know that coefficient of performance of heat pump

 COP=\dfrac{T_{H}}{T_{H}-T_{L}}

So COP=\dfrac{313}{313-283}

      COP=10.43

COP=\frac{Q_{H}}{W_{in}}

      10.43 =\frac{50}{W_{in}}

W_{in}=4.79 KW

So power needed to pump=4.79 KW.

3 0
4 years ago
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