Answer:
78 MPa
Explanation:
Given that the critical resolved shear stress for a metal is 39 MPa, the maximum possible yield strength for a single crystal of this metal is twice the critical resolved shear stress for the metal. The maximum yield yield strength for a single crystal of this metal that is pulled in tension (
) is given as:

The maximum volume flow rate of kerosene is 8.3 L/s
<h3>What is the maximum volume flow rate?</h3>
In fluid dynamics, the maximum volume flow rate (Q) is the volume or amount of fluid flowing via a required cross-sectional area per unit time.
In fluid mechanics, using the following relation, we can determine the maximum volume flow rate of kerosene.
- Power = mass flow rate(m) × specific work(w) --- (1)
- Specific work = acceleration due to gravity (g) × head (h) ---- (2)
- Mass flow rate (m) = density (ρ) × volume flow rate (Q) --- (3)
By combining the three equations together, we have:
The power gained through the fluid pump to be:
Making Q the subject, we have:

where:
- P = 2 kW = 2000 W
- ρ = 0.820 kg/L
- g = 9.8 m/s
- h = 30 m

Q = 0.008296 m³/s
Q ≅ 8.3 L/s
Learn more about the maximum volume flow rate here:
brainly.com/question/19091787
Answer:All of the above
Explanation:
9.62 psi means 497.49 mm of Hg pressure
for (a)19.58 inches is equals to 497.49 mm of Hg
(b)atmospheric pressure is 14.69 psi
vaccum gauge is 9.62psi
absolute pressure is=14.69-9.62=5.07
(c)vaccum means air is sucked and there is negative pressure so it tells about below atmospheric pressure.
thus all are correct
Answer:
hello your question incomplete attached below is the complete question and detailed solution
Answer : Csf = 0.0131
Explanation:
Attached below is the detailed solution
Given data :
ΔTe = 17.1⁰c calculated as ;Ts - Tsat = ( 117.1 - 100 )
Pe = 957.9 kg/m^3
Cp1e = 4217 j/kgk
<em>U</em>e = 279 * 10^-6 n. s / m^2
Pre = 1.76
hfg = 2.257 * 10^6 J/kg
Pv = 0.5955 kg/m^3
б = 0.0589 N/m
q" = 664 * 10^3 w/m^2 ( calculated )
Input these values into equation 1 as contained in the detailed solution
Csf = 0.0131
Answer:
Power needed to pump=4.79 KW.
Explanation:
Given that:
We know that coefficient of performance of heat pump
COP=
So COP=
COP=10.43
COP=
10.43 =
=4.79 KW
So power needed to pump=4.79 KW.