Answer:
Refrigerant R-134a is to be cooled by waterin a condenser.The refrigerant enters thecondenser with a mass flow rate of 6 kg/minat 1 MPa and 70 C and exits at 35 C. The cool-ing water enters at 300 kPa and 15 C andleaves at 25 C. Neglecting pressure drops,determine a) the required mass flow rate ofthe cooling water, and b) the heat transferrate from the refrigerant to the water.SolutionFirst consider the condenser as the control volume. The process is steady,adiabatic and no work is done. Thus over any time intervalΔt,ΔEΔt=0and thusXin˙E=Xout˙Ewhere˙E=˙m h+12V2+gz650:351 Thermodynamics·Prof. Doyle Knight37
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Answer:
Marco is an Italian architect. He has received a contract to design a spacious building.
Explanation:
ect.
Answer:
Ohm, a german physicist, found experimentally that the current in a metal conductor is directly proportional to the potential difference across its ends
Explanation:
Answer:

Explanation:
Given that diameter of tube= 20 mm
flow rate = 72 lt/hr
The properties of SAE 30 oil at 30°C


We know that volume flow rate Q= AV

V= 0.064 m/s
Now lets find Reynolds number to check the type of flow


Re=7.18 So we can say that this is laminar flow and we know that pressure drop for laminar flow is given as

Now by putting the values the pressure drop for per unit length


Solution :
Given
The number of line that can be written by printer per page = 50 lines
The number of characters that can be written by printer per page = 80 characters.
Number of pages that can be written per minute = 6 pages
The speed for writing characters to the printer can be found by
= 50 x 80 x 6
= 400 characters per sec
In one second the printer has the writing speed of 400 character.
Now each of the character uses = 50 µsec of the CPU time for interrupt.
So in each second, the interrupt overhead = 20 msec
Now using the interrupt driven input/output, 980 msec time can be available for other work.
Thus, the interrupt overhead charges only 2 percent of the CPU, that will hardly affect the program to run.