B. Are produced only by living things
1.) 28.0 grams of oxygen
28 grams (1 mole/16 grams per mole)=1.75 moles oxygen
2.)5.0 moles of Iron
5 moles(55.845 grams/1 mole)=279.225 grams Iron
3.) 452 grams Argon
452 grams(1 mole/39.948 grams)=11.315 moles Argon
4.) 16.5 moles Hydrogen
16.5 moles(1.01 grams/1 mole)=16.665 grams Hydrogen
Answer:
0.5mol/L
Explanation:
First, let us calculate the number of mole NaOH = 23 + 16 + 1 = 40g/mol
Mass of NaOH from the question = 30g
Number of mole = Mass /Molar Mass
Number of mole = 30/40 = 0.75mol
Volume = 1.5L
Active mass = mole/Volume
Active mass = 0.75mol/1.5L
Active mass = 0.5mol/L
Answer:
PV=nRT
Explanation:
V=<u>R</u><u>T</u><u>n</u>
P
rearrangement gives
nT
where P=pressure
V=volume
n=number of moles
R=ideal gas(0.0820atmdm/3 mol/k)
T=temperature in kelvin
The given question is incomplete. The complete question is:
A sample of household ammonia has a pH of 11.50. What is the hydronium ion concentration of this solution?
Answer: The hydronium ion concentration of the solution is 
Explanation:
pH or pOH is the measure of acidity or alkalinity of a solution.
pH is calculated by taking negative logarithm of hydrogen ion concentration. Acids have pH ranging from 1 to 6.9 and bases have pH ranging from 7.1 to 14.

![pH=-\log [H^+]](https://tex.z-dn.net/?f=pH%3D-%5Clog%20%5BH%5E%2B%5D)
![11.8=-log [H^+]](https://tex.z-dn.net/?f=11.8%3D-log%20%5BH%5E%2B%5D)
![[H^+]=antilog(-11.8)](https://tex.z-dn.net/?f=%5BH%5E%2B%5D%3Dantilog%28-11.8%29)
![[H^+]=1.58\times 10^{-12}M](https://tex.z-dn.net/?f=%5BH%5E%2B%5D%3D1.58%5Ctimes%2010%5E%7B-12%7DM)
Thus hydronium ion concentration of this solution is 