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3 years ago

Dbv-qyag-dsc.join this now on meet

Physics

2 answers:

Gre4nikov [31]3 years ago

5 0

Answer:

oh you guys never leave this meet question

Explanation:

I am so bored and please leave this business

Sveta_85 [38]3 years ago

3 0

I’m good! :)

But I hope you’re not bored anymore

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How do you get a tachyionic particle and how are they faster than light

melomori [17]

<span>Tachyons are studied in an area called particle physics, and I must say this is a bit out of my league, but I'll give you some general thoughts. Tachyons are hypothetical particles resulting from what physicists call a thought experiment. Back in the 1960s, some physicists wondered what would happen if matter could travel faster than the speed of light, something that is supposed to be impossible according to the Theory of Relativity. So these particles may or may not exist because they have not been proven or disproven by real experiment as of yet. What people have done is apply existing formulas to the unique properties of tachyons (like imaginary mass!). What comes out is a particles that go faster when they lose energy with a MINIMUM velocity of the speed of light and a maximum velocity of infinity! Hope that helps Ben, theoretical physics is a weird place and is not too far off from philosophy.</span>

4 0

3 years ago

What happens to a light wave when it travels from air glass?

iVinArrow [24]

Its speed decreases, its wavelength increases, and its frequency Remains the Same.

5 0

4 years ago

During a visit to the beach, you get in a small rubber raft and paddle out beyond the surf zone. Tiring, you stop and take a res

Monica [59]

Answer:

The main difference in these two movements is that the first is a pure swing movement and the followed form a wave travels from the beach

Explanation:

The movement in the two parts is very different, when the surf zone has passed it is in a deeper part of the water where the seabed does not rise much, therefore due to the movement of the waves there is an upward oscillatory movement and descending, in this movement there is no horizontal displacement.

When it is within the southern zone, there is a rapid rise of the sea floor, which generates a horizontal movement, having a traveling wave, therefore your movement is more complicated, you can have some oscillating movement on the axis and, but in addition to this you have a horizontal movement that reaches you towards the beach, forming a Traveling wave.

The main difference in these two movements is that the first is a pure swing movement and the followed form a wave travels from the beach

3 0

3 years ago

The ideas that the universe began at a single point and has been expanding since its formation are the main premises of which of

Basile [38]

The big bang theory describes and claims that the universe has been created through cosmic expansion originating from a single point.

Where it was explained that the nature of now objects in space being in constant space was due to once a high density and high density point produce a scattering or explosion of the cosmic energy . Other theories have also supported this theory originally and first documented by Georges Henri Joseph Édouard Lemaître an astronomer and physicist.

6 0

3 years ago

A student stretches a spring, attaches a 1.20 kg mass to it, and releases the mass from rest on a frictionless surface. The resu

Sphinxa [80]

Answer:

the speed of the mass when it is halfway to the equilibrium position is 1.26 m/s

Explanation:

Given that;

mass of the object m = 1.20 kg

period of oscillation = 0.750 s

Amplitude ( A/x) = 15.0 cm = 0.15 m

now;

a) Determine the oscillation frequency;

oscillation frequency f = 1/T

we substitute

f = 1 / 0.750 s

f = 1.33 Hz

Therefore, the oscillation frequency is 1.33 Hz

b) Determine the spring constant;

we solve for spring constant from the following expression;

T = 2π√(m/k)

k = 4π²m / T²

so we substitute

k = (4π² × 1.20) / (0.750)²

k = 47.3741 / 0.5625

k = 84.22 N/m

Therefore, the spring constant is 84.22 N/m

c) determine the speed of the mass when it is halfway to the equilibrium position

So, at equilibrium, the energy is equal to K.E

such that;

1/2mv² = 1/2kx²

mv² = kx²

v² = kx² / m

v = √( kx²/m)

we substitute

v = √( 84.22×(0.15 m)²/ 1.2 )

v = √( 1.89495 / 1.2 )

v = √ 1.579125

v = 1.26 m/s

Therefore, the speed of the mass when it is halfway to the equilibrium position is 1.26 m/s

3 0

3 years ago

Dbv-qyag-dsc.join this now on meet​

Dbv-qyag-dsc.join this now on meet