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qwelly [4]
3 years ago
11

What is the resulting velocity of the launcher if the net force on the launcher is equal to the reaction force?

Physics
1 answer:
xz_007 [3.2K]3 years ago
5 0

Answer:

according to this question best answer is C

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Use the image below to answer the following question (ruler not to scale).
Svetradugi [14.3K]

Answer:

it depends on wether the + and - are facing eachother

or away from eachother

Explanation:

4 0
3 years ago
Read 2 more answers
Why is sun called a source of light??​
mote1985 [20]

Answer:

because he give heat and energy

3 0
3 years ago
If I turn on a light in a spaceship traveling 1C BACKWARDS, what happens to the photons? Speed -0-, or 1C in opposite direction?
Advocard [28]

If the spaceship's Physicist happens to be hanging out of one side
of the ship, and he measures the speed of the photons as they pass
him and leave the ship, he'll see them passing him at 'c' ... the speed
of light.

When those photons pass somebody who happens to be in their
path, and he decides to measure their speed, he'll see them move
past him at 'c' ... the speed of light.
 
It doesn't matter whether the observer who measures them is
moving, or at what speed.

And it doesn't matter what source the photons come from, or
whether the source is moving, or at what speed.

And it doesn't matter what the photons' wavelength/frequency is ...
anything from radio to gamma rays.

The photons pass everybody at 'c' ... the speed of light.

Yes, I hear you.  That can't be true. It's crazy.
Maybe it's crazy, but it's true.

5 0
3 years ago
Could you help me with this question?
Scorpion4ik [409]

Answer:

Magnitude of static friction force is 70 sin40° = 44.99 N.  

No, it is not necessary that it is maximum static friction.

Normal force is equal to 70 cos40° = 53.62 N.

Explanation:

We apply newton law of moton equation along the plane and perpendicular to plane;

Along the plane,

70 sin 40° = f_{r}  ---------------(1)

70 cos 40° = N --------------(2)

f_{r}_{max} = μN -----------------(3)

So, it depends on the value of μ that the friction is maximum or not .

7 0
3 years ago
Radiation emitted from human skin reaches its peak at λ = 960 µm. what is the frequency of this radiation? planck's constant is
Artist 52 [7]
1) The wavelength of the radiation emitted by the human skin is
\lambda=960 \mu m = 960 \cdot 10^{-6} m
the frequency of the radiation is related to the wavelength by
f= \frac{c}{\lambda}
where c=3 \cdot 10^8 m/s is the speed of light. Plugging numbers into the formula, we find the frequency of the radiation:
f= \frac{3 \cdot 10^8 m/s}{960 \cdot 10^{-6}m}=3.13 \cdot 10^{11} Hz

2) The frequency of this radiation is 313 GHz, and its wavelength 960 \mu m. If we look at the table of the electromagnetic spectrum
https://en.wikipedia.org/wiki/Electromagnetic_spectrum
We see that we are in the range of visible light (in particular, in the infrared range).
Therefore, the correct answer is <span>2. visible light .</span>
6 0
3 years ago
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