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qwelly [4]
3 years ago
11

What is the resulting velocity of the launcher if the net force on the launcher is equal to the reaction force?

Physics
1 answer:
xz_007 [3.2K]3 years ago
5 0

Answer:

according to this question best answer is C

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Which are heterogeneous mixtures?
inna [77]
C. Sugars dissolved in water
4 0
3 years ago
For a constant voltage, how is the resistance related to the current?
Aleksandr-060686 [28]

Answer:

Resistance is inversely proportional to current, so when the resistance doubles, the current is cut in half. Resistance is directly proportional to current, so when the resistance doubles, the current is cut in half.

8 0
2 years ago
an object is thrown with an initial horizontal velocity of 10 meters per second and take approximately 9 seconds to reach the gr
pantera1 [17]

The horizontal velocity was constant, so:

s = vt

s = 10\cdot9

s = 90

it traveled 90meters

6 0
3 years ago
Suppose you have two solid bars, both with square cross-sections of 1 cm2. They are both 24.6 cm long, but one is made of copper
vodka [1.7K]

Explanation:

Expression to calculate thermal resistance for iron (R_{I}) is as follows.

             R_{I} = \frac{L_{I}}{k_{I} \times A_{I}}  

where,   L_{I} = length of the iron bar

             k_{I} = thermal conductivity of iron

             A_{I} = Area of cross-section for the iron bar

Thermal resistance for copper (R_{c}) = \frac{L_{c}}{k_{c} \times A_{c}}[/tex]

where,  L_{c} = length of copper bar

             k_{c} = thermal conductivity of copper

            A_{c} = Area of cross-section for the copper bar

Now, expression for the transfer of heat per unit cell is as follows.

           Q = \frac{(100^{o} - 0^{o}}{\frac{L_{I}}{k_{I}.A_{I}} + \frac{L_{c}}{k_{c}.A_{c}}}

 Putting the given values into the above formula as follows.

       Q = \frac{(100^{o} - 0^{o})}{\frac{L_{I}}{k_{I}.A_{I}} + \frac{L_{c}}{k_{c}.A_{c}}}

  = \frac{(100^{o} - 0^{o})}{21 \times 10^{-2} m[\frac{1}{73 \times 10^{-4}m^{2}} + \frac{1}{386 \times 10^{-4}m^{2}}}

           = 2.92 Joule

It is known that heat transfer per unit time is equal to the power conducted through the rod. Hence,

                 P = \frac{Q}{T}

Here, T is 1 second so, power conducted is equal to heat transferred.

So,           P = 2.92 watt

Thus, we can conclude that 2.92 watt power will be conducted through the rod when it reaches steady state.

7 0
3 years ago
Considera que en tu casa tienes un televisor de 110 W, si pasa encendido 4 horas diarias, Cuál será la energía consumida durante
rjkz [21]

Answer:

 E = 13.2 kWh

,     Cost = $ 10.8

Explanation:

We can look for the consumed energy from the expression of the power

      P = W / t

The work is equal to the variation of the kinetic energy, for which

       P = E / t

       E = P t

       

look for the energy consumed in one day and multiply by the days of the month in the month

      E = 110 4 30

      E = 13200 W h

       E = 13.2 kWh

the cost of this energy is

    Cost = 0.9 12

    Cost = $ 10.8

4 0
3 years ago
Read 2 more answers
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