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Andreas93 [3]
4 years ago
10

Find the equation of the vertical line that passes through the point (3,-5).

Mathematics
2 answers:
iogann1982 [59]4 years ago
6 0
Your answer is 3 as this is the x axis and -5 will pass through your y axis
Sever21 [200]4 years ago
3 0
3/-5 (3 over -5)

hopefully i could help
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Solve the system of equation please help , I would greatly appreciate it
xz_007 [3.2K]

Answer: Your answer is going to be D. (10, -1)


Step-by-step explanation:

Starting off the equation you want to get rid of either x or y ( I did x first)

Take x+3y=7 and multiply the entire equation by -2 -- -2(x+3y=7)

You get -2x-6y=-14 and then add the two equations together

-2x-6y=-14

2x-4y=24  -- You get -10y = 10

y = -1

You can take the -1 and plug it back into either equation.. ( I did x+3y=7)

x+3(-1)=7 -- x-3=7 -- Add the 3 to get the 10 ( x = 10 )

So you have x = 10 & y = -1

(10,-1)




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3 years ago
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HACTEHA [7]
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6 0
3 years ago
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Help me soon please
STALIN [3.7K]

Answer:

i’m pretty sure the answer is b

7 0
3 years ago
Can someone help me in #66
VladimirAG [237]
\bf log_{{  a}}(xy)\implies log_{{  a}}(x)+log_{{  a}}(y)
\\ \quad \\
% Logarithm of rationals
log_{{  a}}\left(  \frac{x}{y}\right)\implies log_{{  a}}(x)-log_{{  a}}(y)
\\ \quad \\
% Logarithm of exponentials
log_{{  a}}\left( x^{{  b}} \right)\implies {{  b}}\cdot  log_{{  a}}(x)\\\\
-------------------------------\\\\


\bf log_4\left( \cfrac{\sqrt{x^5y^7}}{zw^4} \right)\implies log_4(\sqrt{x^5y^7})-log_4(zw^4)
\\\\\\
log_4\left[(x^5y^7)^{^\frac{1}{2}}\right]-log_4(zw^4)\implies 
\cfrac{1}{2}log_4\left[(x^5y^7)\right]-log_4(zw^4)
\\\\\\
\cfrac{1}{2}\left[ log_4(x^5)+log_4(y^7) \right] -[log_4(z)+log_4(w^4)]
\\\\\\
\cfrac{1}{2}log_4(x^5)+\cfrac{1}{2}log_4(y^7)-[log_4(z)+log_4(w^4)]

\bf \cfrac{1}{2}\cdot 5log_4(x)+\cfrac{1}{2}\cdot 7log_4(y)-log_4(z)-4log_4(w)
\\\\\\
\cfrac{5}{2}log_4(x)+\cfrac{7}{2}log_4(y)-log_4(z)-4log_4(w)
6 0
3 years ago
make up an equation in the form of an y=kx +b, the graph which passes through the following points: (5,5) and (-10,-19)
Oksana_A [137]

Answer:

y = 8/5x - 3

Step-by-step explanation:

First, find the slope using rise over run (y2 - y1) / (x2 - x1)

(y2 - y1) / (x2 - x1)

(-19 - 5) / (-10 - 5)

-24 / -15

= 8/5

Plug in the slope and a given point into y = mx + b, and solve for b

y = mx + b

5 = 8/5(5) + b

5 = 8 + b

-3 = b

Plug in the slope and b into y = mx + b

y = 8/5x - 3

So, the equation is y = 8/5x - 3

8 0
3 years ago
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