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Semenov [28]
3 years ago
11

Element M reacts with oxygen to form an oxide with the formula MO. When MO is dissolved in water, the resulting solution is basi

c. Element M could be ________.Element M reacts with oxygen to form an oxide with the formula MO. When MO is dissolved in water, the resulting solution is basic. Element M could be ________.arsenicgermaniumchlorinecalciumselenium
Chemistry
1 answer:
Tpy6a [65]3 years ago
5 0

Answer:

Calcium

Explanation:

Since the element reacts with oxygen to form an oxide with the formula MO, the charge on the element is +2.

Also, since the oxide MO when dissolved in water is basic, the metal is an alkali earth metal.

From the above conditions;

The metal is not arsenic because arsenic is a metalloid has the  following oxides As₂O₃ and As₃O₅ and are respectively amphoteric and acidic in nature

The metal is not germanium because is a metalloid and even though germanium oxide has the formula GeO₂, it is amphoteric.

The metal is not chlorine because chlorine is a non-metal

The metal is definitely calcium because calcium oxide has the formula CaO and calcium is an alkaline earth metal.

The metal is not selenium because selenium is anon-meal and its oxide has the formula Se0₂ and is acidic

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a) \: n = \frac{N}{NA} \\ 1.5 = \frac{x}{6.02 \times \: {10}^{23} } \\ x = 1.5 \times 6.02 \times {10}^{23} \\ x = 9.03 \times {10}^{23} \: atoms \: of \: Na

b) \: n = \frac{N}{NA} \\ 0.25 = \frac{x}{6.02 \times \: {10}^{23} } \\ x = 0.25 \times 6.02 \times {10}^{23} \\ x = 1.505 \times {10}^{23} \: atoms \: of \: Si \:
c) \: n = \frac{N}{NA} \\ 6.755 = \frac{x}{6.02 \times \: {10}^{23} } \\ x = 6.755 \times 6.02 \times {10}^{23} \\ x = 40,6651 \times {10}^{23} \\ x = 4.07 \times {10}^{24} \: atoms \: of \: Pb \:
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3 years ago
Substances that absorb energy in the form of heat are
Yanka [14]

Answer:

Substances that absorb energy in the form of heat are

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Consider the following mechanism for the formation of tert-butanol: (CH_3)_3CBr(aq) rightarrow (Ch_3)_3 C^+ (aq) + Br^- (aq) (CH
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Answer:

The mechanism is in the attached file. The reaction intermediates are the following: C4H8O, C4H9O

Explanation:

Terbutanol is a tertiary alcohol. It is one of the four isomers of butanol. It is a transparent liquid (or a colorless solid, depending on the temperature), with an odor similar to camphor. It is very soluble in water and ethanol.

The scheme shows a protonation of the double bond and the nucleophilic attack of the water to the carbocation, then it loses a proton and the terbutanol is formed.

Download pdf
4 0
3 years ago
Ricky and Shemane, who are stoked to be learning stoich, were working diligently on a chemistry assignment in class. Ricky reali
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Ka for acetic acid, CH3COOH, is 1.80×10-5.Ka for acetylsalicylic acid (aspirin), HC9H7O4, is 3.00×10-4.Ka for benzoic acid, C6H5
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Answer:

The weakest conjugate base is C9H7O4⁻ which is the conjugate base of Aspirin.

Explanation:

The higher the Ka, the stronger the acid thus the weaker its conjugate base.

Ka of the acid are provided:

CH3COOH = 1.80*10-5

HC9H7O4 = 3.00*10-4

C6H5COOH = 6.30*10-5

From the Ka above, HC9H7O4 have the highest therefore its conjugate acid is the weakest.

When it donates the proton, it becomes the conjugate base.

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4 years ago
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