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STALIN [3.7K]
3 years ago
10

Ka for acetic acid, CH3COOH, is 1.80×10-5.Ka for acetylsalicylic acid (aspirin), HC9H7O4, is 3.00×10-4.Ka for benzoic acid, C6H5

COOH, is 6.30×10-5.What is the formula for the weakest conjugate base?
Chemistry
1 answer:
klemol [59]3 years ago
3 0

Answer:

The weakest conjugate base is C9H7O4⁻ which is the conjugate base of Aspirin.

Explanation:

The higher the Ka, the stronger the acid thus the weaker its conjugate base.

Ka of the acid are provided:

CH3COOH = 1.80*10-5

HC9H7O4 = 3.00*10-4

C6H5COOH = 6.30*10-5

From the Ka above, HC9H7O4 have the highest therefore its conjugate acid is the weakest.

When it donates the proton, it becomes the conjugate base.

HC9H7O4 + H2O ⇄ C9H7O4⁻ + H3O⁺

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The density of helium is 0.17 g/L. What Is the mass of helium in a 5.4 L helium balloon? (2 sig figs) *
ioda

Answer:

The correct answer is 0.92 g

Explanation:

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Question 15 need this answered asap (chemistry)
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80.7 L

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Answer:

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