1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
KonstantinChe [14]
3 years ago
14

You pull with a force of 295 N on a rope that is attached to a block of mass 22 kg, and the block slides across the floor at a c

onstant speed of 1.6 m/s. The rope makes an angle of 35 degrees with the horizontal. What is the net force on the block
Physics
1 answer:
Sergeeva-Olga [200]3 years ago
6 0

Answer:

Fnet = 0

Explanation:

  • Since the block slides across the floor at constant speed, this means that it's not accelerated.
  • According Newton's 2nd Law, if the acceleration is zero, the net force on the sliding mass must be zero.
  • This means that there must be a friction force opposing to the horizontal component of the applied force, equal in magnitude to it:

       F_{appx} = F_{app} * cos \theta = 295 N * cos 35 = 242 N  (1)

  • In the vertical direction, the block is not accelerated either, so the sum of the normal force and the vertical component of the applied force, must be equal in magnitude to the force of gravity on the block:

      F_{appy} = F_{app} * cos \theta = 295 N * sin 35 = 169 N  (2)

⇒    169 N + Fn = Fg = 216 N  (3)

  • This means that there must be a normal force equal to the difference between Fappy and Fg, as follows:
  • Fn = 216 N - 169 N = 47  N (4)

You might be interested in
A 2.00-m long uniform beam has a mass of 4.00 kg. The beam rests on a fulcrum that is 1.20 m from its left end. In order for the
Shalnov [3]

Answer:

x ’= 1,735 m,  measured from the far left

Explanation:

For the system to be in equilibrium, the law of rotational equilibrium must be fulfilled.

Let's fix a reference system located at the point of rotation and that the anticlockwise rotations have been positive

             

They tell us that we have a mass (m1) on the left side and another mass (M2) on the right side,

the mass that is at the left end x = 1.2 m measured from the pivot point, the mass of the right side is at a distance x and the weight of the body that is located at the geometric center of the bar

           x_{cm} = 1.2 -1

          x_ {cm} = 0.2 m

          Σ τ = 0

          w₁ 1.2 + mg 0.2 - W₂ x = 0

          x = \frac{m_1 g\ 1.2 \ + m g \ 0.2}{M_2 g}

          x = \frac{m_1 \ 1.2 \ + m \ 0.2 }{M_2}

let's calculate

          x = \frac{2.9 \ 1.2 \ + 4 \ 0.2 }{8.00}2.9 1.2 + 4 0.2 / 8

           

          x = 0.535 m

measured from the pivot point

measured from the far left is

           x’= 1,2 + x

           x'=  1.2 + 0.535

           x ’= 1,735 m

8 0
3 years ago
Suspend a heavy weight by two pieces of rope. Tension is greatest when the ropes
bija089 [108]
Assuming that the angle is the same for both ropes, then D. is the answer.  You have to consider also if the ropes are close together or far apart and if the force to move the object is in line with the ropes or perpendicular to them.
<span />
3 0
3 years ago
Please help me to solve this and give me the summary of answer
Neko [114]
Using the principle of floatation.

u = w............(a)

Upthrust of fluid is equal to the weight of the object.

Let the volume of the wood be V.

The upthrust u, is related to the volume submerged in water, and that is 1/5 of it volume, that is (1/5)V = 0.2V

Formula for upthrust, u = vdg

where v = volume of fluid displaced
d = density of fluid
g = acceleration due to gravity

weight, w = mg
where m = mass
g = acceleration due to gravity

From (a)

                     u = w

                 vdg =  mg      Cancel out g

                   vd  =  m
 
The v  is equal to 0.2V, which is the submerged volume. Notice that the small letter v is volume of fluid displaced, and capital V is the volume of the solid.

d is density of fluid which is water in this case, 1000 kg/m³

         0.2V * 1000 =  m

           200V =  m

Hence the mass of the object is  200V  kg.

But Density of solid =  Mass of solid / Volume of solid

                                 =    200V / V

                                 =    200 kg/m³

Density of solid = 200 kg/m³     
7 0
3 years ago
Paolo says that his bicycle is hard to pedal.Mia looks at the bicycle and tells him he needs to oil the chain.explain why oiling
laila [671]

Answer:

Less friction

Explanation:

Paolo's bike is too difficult to pedal because there is too much friction in the mechanisms of the bike. To reduce friction, Paolo must oil the chain. This will make the bike run much more smoothly and allow for easier pedalling.

6 0
2 years ago
I need help asap!!!
Aleks [24]

Answer:

Probably competition with television news-

by 1953 television was becoming common in many houses and people could obtain news from television newscasts

6 0
2 years ago
Other questions:
  • Meteoroids are small objects in space, usually made of rock or metal. These bodies often get close to a planet and fall through
    12·1 answer
  • You stare at a bright red screen for so long that your red cones become saturated and no longer function. The red screen is then
    6·2 answers
  • What does it mean when white light is diffracted and at a particular location the color seen is blue? Please use 2 content relat
    13·1 answer
  • The amount of space between two points is measure in unit?
    11·2 answers
  • The unit of power is<br>Denved<br>Unit? Why​
    15·1 answer
  • A box that is sliding across the floor experiences a net force of 10.0 N. If the box has a mass of 1.50 kg, what is the resultin
    15·1 answer
  • B. Projectile on cliff (range)
    8·1 answer
  • Helppppp!!!!!! inportant need help with b​
    12·1 answer
  • How does a physicist answer a scientific question?
    6·1 answer
  • find the following Distance, Time, and Velocity in the problem; a track runs a 100-m dash in 11 seconds. What is his average vel
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!