The starting position is 0m. The starting velocity is 30m/s. Time is given as 2.5s. What is the final position of the object?
1 answer:
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Answer:
h = 90.10 m
Explanation:
Given that,
A man is standing near the edge of a cliff 85 meters high, h₀ = 85 m
The initial speed of the stone, u = 10 m/s
The path followed by the projectile is given by :
....(1)
For maximum height,
Put dh/dt = 0
So,
Put the value of t in equation (1).
So, the maximum height of the stone is equal to 90.10 m.