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lord [1]
3 years ago
9

I need help asap thank you marking brainliest

Mathematics
1 answer:
FromTheMoon [43]3 years ago
7 0

Answer:

a_{20} = 12+3(20-1)

Step-by-step explanation:

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The length of the hypotenuse of a right angled triangle exceeds the length of the base by 2cm and exceeds twice the length of th
insens350 [35]

Answer: a = 8;  b = 15;  c = 17

Step-by-step explanation:

c = b + 2  and c = 2a + 1

b = c − 2 and a =  \frac{c-1}{2}

​

c² = b² + a²  

c^{2} = (c-2)^{2} + \frac{c-1}{2}\\

c^{2}= \frac{4 (c-2)^{2}+(c - 1)^{2}  }{4}

4c^{2}={4 (c^{2} + 4 -4c)+c ^{2}  + 1-2c

4c^{2}={4 c^{2} + 16 -16c)+c ^{2}  + 1-2c

c^{2}-18c+17=0

c(c -17)-1(c-17)=0

​(c -1)(c-17)=0

c = 1 or c = 17

If c = 1 then b = 1 - 2 = -1, that's not possible

So x = 17

b = 17 - 2 = 15

a = \frac{17-1}{2}  = 8

Length sides of the triangle are 17 cm, 15 cm and 8 cm.

I saw some of this on a site but I want to make sure its correct so we're gonna apply the pythagorean theory and see if its correct.

a^{2} + b^{2} = c^{2} \\8^{2} + 15^{2} = 17^{2} \\64 + 225 = 289\\289 = 289\\

This shows that this is correct.

Hope this helped! Again, some of this was from a site, not from me.

3 0
3 years ago
<img src="https://tex.z-dn.net/?f=4x%20%5Csqrt%5B%20%2B%2015%20-%2015%5D%7B%3F%7D%20" id="TexFormula1" title="4x \sqrt[ + 15 - 1
blondinia [14]

Answer:

please what subject is this

6 0
3 years ago
Find the perimeter of the figure to the nearest hundredth.
babunello [35]

Answer:

50.28 inches

Step-by-step explanation:

From the Image, we can find the length of the arc of the semi-circle by dividing the circumference of the resulting circle by 2

Radius= 9in

C= 2πr

C=2*3.142*9

C=2*3.142*9

C= 56.556 inches

Hence the length of the arc is

=56.556/2

=28.278 inches

The perimeter of the shape

=28.278+5+12+5

=50.28 inches

8 0
3 years ago
Write an expression for the sequence of operations described below.
Triss [41]

Answer:

(h+g)=n➗2 is the answer. happy to help you

5 0
3 years ago
6. Consider the A = LR factorization of the matrix A: A =   1 0 0 1 1 0 0 1 1     0 3 2 3 4 0 0 0 2 4 0 0 0 0 0   withou
Natali [406]

Answer:

Please see attachments for step by step guide and answers.

8 0
3 years ago
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