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3 years ago

I need help asap thank you marking brainliest

Mathematics

1 answer:

FromTheMoon [43]3 years ago

7 0

Answer:

$a_{20} = 12+3(20-1)$

Step-by-step explanation:

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The length of the hypotenuse of a right angled triangle exceeds the length of the base by 2cm and exceeds twice the length of th

insens350 [35]

Answer: a = 8; b = 15; c = 17

Step-by-step explanation:

c = b + 2 and c = 2a + 1

b = c − 2 and a = $\frac{c-1}{2}$

c² = b² + a²

$c^{2} = (c-2)^{2} + \frac{c-1}{2}\\$

$c^{2}= \frac{4 (c-2)^{2}+(c - 1)^{2} }{4}$

$4c^{2}={4 (c^{2} + 4 -4c)+c ^{2} + 1-2c$

$4c^{2}={4 c^{2} + 16 -16c)+c ^{2} + 1-2c$

$c^{2}-18c+17=0$

$c(c -17)-1(c-17)=0$

$(c -1)(c-17)=0$

c = 1 or c = 17

If c = 1 then b = 1 - 2 = -1, that's not possible

So x = 17

b = 17 - 2 = 15

a = $\frac{17-1}{2} = 8$

Length sides of the triangle are 17 cm, 15 cm and 8 cm.

I saw some of this on a site but I want to make sure its correct so we're gonna apply the pythagorean theory and see if its correct.

$a^{2} + b^{2} = c^{2} \\8^{2} + 15^{2} = 17^{2} \\64 + 225 = 289\\289 = 289\\$

This shows that this is correct.

Hope this helped! Again, some of this was from a site, not from me.

3 0

3 years ago

<img src="https://tex.z-dn.net/?f=4x%20%5Csqrt%5B%20%2B%2015%20-%2015%5D%7B%3F%7D%20" id="TexFormula1" title="4x \sqrt[ + 15 - 1

blondinia [14]

Answer:

please what subject is this

6 0

3 years ago

Find the perimeter of the figure to the nearest hundredth.

babunello [35]

Answer:

50.28 inches

Step-by-step explanation:

From the Image, we can find the length of the arc of the semi-circle by dividing the circumference of the resulting circle by 2

Radius= 9in

C= 2πr

C=2*3.142*9

C= 56.556 inches

Hence the length of the arc is

=56.556/2

=28.278 inches

The perimeter of the shape

=28.278+5+12+5

=50.28 inches

8 0

3 years ago

Write an expression for the sequence of operations described below.

Triss [41]

Answer:

(h+g)=n➗2 is the answer. happy to help you

5 0

3 years ago

6. Consider the A = LR factorization of the matrix A: A =   1 0 0 1 1 0 0 1 1     0 3 2 3 4 0 0 0 2 4 0 0 0 0 0   withou

Natali [406]

Answer:

Please see attachments for step by step guide and answers.

8 0

3 years ago