Answer:
16 g Ag
General Formulas and Concepts:
<u>Chemistry - Stoichiometry</u>
- Using Dimensional Analysis
<u>Chemistry - Atomic Structure</u>
Explanation:
<u>Step 1: Define</u>
[RxN] Cu (s) + AgNO₃ (aq) → CuNO₃ (aq) + Ag (s)
[Given] 25 g AgNO₃
<u>Step 2: Identify Conversions</u>
[RxN] 1 mol AgNO₃ = 1 mol Ag
Molar Mass of Ag - 107.87 g/mol
Molar Mass of N - 14.01 g/mol
Molar Mass of O - 16.00 g/mol
Molar Mass of AgNO₃ - 107.87 + 14.01 + 3(16.00) = 169.88 g/mol
<u>Step 3: Stoichiometry</u>
<u />
= 15.8744 g Ag
<u>Step 4: Check</u>
<em>We are given 2 sig figs. Follow sig fig rules and round.</em>
15.8744 g Ag ≈ 16 g Ag
Mendeleev’s chart allotted spaces for elements that were yet to be discovered. For some of these missing pieces, he predicted what their atomic masses and other chemical properties would be.
The unit of measurement for speed is the ratio of two - the meter per second.
Answer: 3.295moles
Explanation:Please see attachment for explanation