Given that the mass of the toy cart is 2.0 kg and and the acceleration is unknown, the normal formula would be a=f/m where a is acceleration, f is force and m is mass but the string's breaking strength is 40n so I think the formula in this case will be f is greater than m*a
40 is greater than 2a
40 is greater than 2a
40/2 is greater than 2a/2
20m/s² is greater than a
Therefore the maximum speed the toy cart should have should be less than 20m/s²
Kinetic Energy = (1/2) mv^2.
m = 57.7 g = 57.7/1000 = 0.00577 kg.
v = 325 m/s.
E = 0.5 * 0.00577 * 325^ 2. Use your calculator.
E = 304.728125 J.
That's the kinetic energy.
F = G m1*m2 / r^2 => [G] = [F]*[r]^2 /([m1]*[m2]) = N * m^2 / kg^2
That is one answer.
Also, you can use the fact that N = kg*m/s^2
[G] = kg * m / s^2 * m^2 / kg^2 = m^3 /(s^2 * kg)
When a wire is moved inside uniform magnetic field then its free electrons will experience magnetic force on it due to which wire will have potential difference at its ends.
Now here we will have magnetic field due to earth and wire is moving in this constant field so induced emf is given by formula
given that
now by using the above formula we will have
They were published in 1542.
