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navik [9.2K]
3 years ago
10

Which phrase best describes the time period in which the current body of scientific knowledge was developed? A. Just over the la

st 50 years B. Throughout all of history C. Mostly in the 20th century D. Mostly during Roman times
Physics
1 answer:
LiRa [457]3 years ago
3 0

Answer:

The correct option is;

B. Throughout all of history

Explanation:

A body of knowledge comprises of a given collection of concepts, activities and terms that represents a professional discipline that is outlined by the associated scholarly society, therefore, scientific knowledge, being comprised of very diverse field of knowledge, with different approaches and  changing understanding is taking as a process of learning about the universe data collection, experimenting analysis and communication with a theme of systems, equilibrium, models and constant change which makes the basis of the body of scientific knowledge to be throughout all of history.

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Colt1911 [192]

Answer:

The  the average magnitude of the force exerted on the ball by the floor 11.2 \times 10^{3} N

Explanation:

Given:

Mass of ball m = 0.4 kg

Initial speed v_{i} = -8 \frac{m}{s}

Rebound speed v_{f} = 6 \frac{m}{s}

Contact time interval \Delta t = 0.5 \times 10^{-3} sec

For finding the average magnitude of the force on the ball by the floor is given by,

   F_{avg}  = \frac{\Delta P}{\Delta t}

Here \Delta P = m (v_{f}- v_{i} )

   F_{avg} = \frac{m (v_{f} -v_{i}  )}{\Delta t}

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Therefore, the  the average magnitude of the force exerted on the ball by the floor 11.2 \times 10^{3} N

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3 years ago
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Andru [333]

Answer:

1000 millimeters

Explanation:

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What type of physical weathering is most common in a river
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Exfoliation or Unloading. As upper rock portions erode, underlying rocks expand. ...

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4 years ago
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A boy whirls a stone in a horizontal circle of radius 1.8 m and at height 1.8 m above level ground. The string breaks, and the s
umka2103 [35]

Answer:

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Solution:

As per the question:

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Height above the ground, h = 1.8 m

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Now,

The magnitude of the centripetal acceleration can be calculated as:

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where

v = velocity

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a_{c} = centripetal acceleration

Now, if we consider the vertical component of motion only, then considering the initial velocity, 'u' = 0, from kinematic eqn:

h = ut + \frac{1}{2}gt^{2}                

h = 0.t + \frac{1}{2}gt^{2}                

t = \sqrt{\frac{2h}{g}}                

t = \sqrt{\frac{2\times 1.8}{9.8}}

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Explanation:

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