Answer: learn how to do it on your own idiot
Explanation: try hard in school
Answer:
t = √2y/g
Explanation:
This is a projectile launch exercise
a) The vertical velocity in the initial instants (
= 0) zero, so let's use the equation
y =
t -1/2 g t²
y= - ½ g t²
t = √2y/g
b) Let's use this time and the horizontal displacement equation, because the constant horizontal velocity
x = vox t
x = v₀ₓ √2y/g
c) Speeds before touching the ground
vₓ = vox = constant
=
- gt
= 0 - g √2y/g
= - √2gy
tan θ = Vy / vx
θ = tan⁻¹ (vy / vx)
θ = tan⁻¹ (√2gy / vox)
d) The projectile is higher than the cliff because it is a horizontal launch
Answer:


Explanation:
From the question we are told that
Velocity of aircraft 
Engine air intake rate 
Fuel burn rate 
Velocity of exhaust gas 
Generally the Mass change rate of Rocket is mathematically given by



Generally the Trust of the rocket is given mathematically by



Generally the Rocket's delivered power is mathematically given by
Delivered power P



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Answer:
the x and y values
Explanation:
because on the table the x is the input and y is the output