Since the frequency of sound in a medium is constant, therefore, the concert-goers would hear the low notes and high notes at the same time.
<h3>What is a dispersive medium?</h3>
A dispersive medium is a medium which spreads out or disperses a substance passing through it.
Since CO2 is a dispersive medium, it means sound waves passing through it would be dispersed based on wavelength.
The note of a sound depends on its frequency, the higher the frequency, the higher the note.
Frequency of sound is constant, therefore, the concert-goers would hear the low notes and high notes at the same time.
Learn more about dispersion of sound at: brainly.com/question/781734
Answer:
False you dont repaint your hamster.
Explanation:
LOL
Answer: 0.01 m
Explanation: The formulae for capillarity rise or fall is given below as
h = (2T×cosθ)/rpg
Where θ = angle mercury made with glass = 50°
T = surface tension = 0.51 N/m
g = acceleration due gravity = 9.8 m/s²
r = radius of tube = 0.5mm = 0.0005m
p = density of mercury.
h = height of rise or fall
From the question, specific gravity of density = 13.3
Where specific gravity = density of mercury/ density of water, where density of water = 1000 kg/m³
Hence density of mercury = 13.3×1000 = 13,300 kg/m³.
By substituting parameters, we have that
h = 2×0.51×cos 50/0.0005×9.8×13,300
h = 0.6556/65.17
h = 0.01 m
Answer:
1 angstrom = 0.1nm
5000 angstrom = 5000/1 × 0.1nm
<h3>= 500nm</h3>
5000 angstrom = 5000 × 1 × 10^-10
<h3>= 5 × 10^-7 m</h3>
Hope this helps you
Answer:
The swimmer has a distance traveled of 800 meters.
The final displacement of the swimmer is 0 meters.
Explanation:
A lap is a round trip made by a swimmer in the pool, so that the distance traveled by swimmer is sixteen times the length of the swimming pool. That is:
A swimmer has a distance traveled of 800 meters.
The displacement is the distance between swimmer and a reference point, let suppose that reference point is located at the beginning of the first lap. Hence, the final displacement of the swimmer is 0 meters.
