PEMDAS
15-(37+8)/3
15-45/3
15-15
0
If the length of a rectangle is a two-digit number with identical digits and the width is 1/10 the length and the perimeter is 2 times the area of the rectangle, what is the the length and the width
Solution:
Let the length of rectangle=x
Width of rectangle=x/10
Perimeter is 2(Length+Width)
= 2(x+x/10)
Area of Rectangle= Length* Width=x*x/10
As, Perimeter=2(Area)
So,2(x+x/10)=2(x*x/10)
Multiplying the equation with 10, we get,
2(10x+x)=2x²
Adding Like terms, 10x+x=11x
2(11x)=2x^2
22x=2x²
2x²-22x=0
2x(x-11)=0
By Zero Product property, either x=0
or, x-11=0
or, x=11
So, Width=x/10=11/10=1.1
Checking:
So, Perimeter=2(Length +Width)=2(11+1.1)=2*(12.1)=24.2
Area=Length*Width=11*1.1=12.1
Hence, Perimeter= 2 Area
As,24.2=2*12.1=24.2
So, Perimeter=2 Area
So, Answer:Length of Rectangle=11 units
Width of Rectangle=1.1 units
Answer:
25000m/s
Step-by-step explanation:
The following formula is used to calculate the speed or velocity of a wave.
V = f * w
Where V is the velocity (m/s)
f is the frequency (hz)
w is the wavelength (m)
First, determine the frequency.
Calculate the frequency of the wave.
Next, determine the wavelength.
Calculate the wavelength of the wave.
Finally, calculate the wave speed.
Using the formula above, calculate the wave speed.
Answer:
the formula is VAT %op cp ×13500 do that using this formul6 is should correct
