4. A force of 6.0 Newtons is applied to a block at rest on a horizontal frictionless surface over a 7.0 meter span. How much ene
1 answer:
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Explanation:
It is given that,
The velocity of a particle is given by :
Where
v is in m/s and t is in seconds
Let a is the acceleration of the object at time t. So,
When a = 0
t = 2.5 s
a is zero at t = 2.5 s. Velocity,
v = -75 m/s
Since, , s is the distance travelled
At t = 2.5 s,
s = −83.34 m
Hence, this is the required solution.
Answer:
42 m
Explanation:
= initial velocity of the car = 24 m/s
= final velocity of the car = 0 m/s
μ = coefficient of kinetic friction = 0.7
g = acceleration due to gravity = 9.8 m/s²
a = acceleration due to kinetic frictional force = - μg = - (0.7)(9.8) = - 6.86 m/s²
d = distance through which the car skids
Using the kinematics equation
Inserting the values
d = 42 m