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leonid [27]
1 year ago
6

a dragster gets to a peed of 112m/s over a distance of 300m from rest. Determine the acceleration of the dragster.

Physics
1 answer:
madreJ [45]1 year ago
3 0

A dragster gets to a speed of 112 m/s over a distance of 300 m from the rest, then the acceleration will be 20.9 m/s².

<h3>What is Acceleration?</h3>

The rate of change in an object's velocity with respect to time is known as acceleration in mechanics. The vector quantity of accelerations. The direction of the net force that is acting on an object determines its acceleration.

Since acceleration has both a magnitude and a direction, it is a vector quantity. Velocity is a vector quantity as well. The definition of acceleration is the change in velocity vector over a time interval divided by the time interval.

According to the question, the given values are :

Final velocity, v = 112 m/s.

Initial velocity, u = 0 m/s

Distance, s = 300 m.

Use the equation of motion,

v² - u² = 2as

112 ² - 0 = 2 (a)(300)

a = 12544/600

a = 20.9 m/s².

Hence, the acceleration of the dragster will be 20.9 m/s².

To get more information about Acceleration :

brainly.com/question/20382454

#SPJ1

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