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3 years ago

What is your hypothesis (or hypotheses) for this experiment?

2 answers:

6 0

Answer: In that case, Put something like "My hypothesis is that the car will take (x) seconds to get to checkpoint 1, (x) seconds to get to checkpoint 2, (x) seconds to get to checkpoint 3, and (x) seconds to get to checkpoint 4" Replacing x with random numbers, or number close to the actual found numbers, but honestly as long as the guesses arent outrageous you should get the question right

Explanation:

Alex787 [66]3 years ago

4 0

Answer:

My hypothesis is that the car will take (x) seconds to get to checkpoint 1, (x) seconds to get to checkpoint 2, (x) seconds to get to checkpoint 3, and (x) seconds to get to checkpoint 4.

This above is a good starter the hypothesis.

Explanation:

I am literally here struggling to write a lab report because I didn't pay any attention while doing this lab project.

I didn't even record the seconds it took for the race cars to get to each checkpoint. ;; very d u m b move, correct, I know it was. I really regret it now. I never knew we had to write a whole lab report for it.

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Which planet is the farthest terrestrial planet from the Sun?

Ivanshal [37]

THE ANSWER IS B.MERCURY

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3 years ago

What is the orbital period of a spacecraft in a low orbit near the surface of mars? The radius of mars is 3.4×106m.

valkas [14]

<h2>Answer: 56.718 min</h2>

Explanation:

According to the Third Kepler’s Law of Planetary motion<em> </em><em>“The square of the orbital period of a planet is proportional to the cube of the semi-major axis (size) of its orbit”. </em>

In other words, this law states a relation between the orbital period $T$ of a body (moon, planet, satellite) orbiting a greater body in space with the size $a$ of its orbit.

This Law is originally expressed as follows:

$T^{2}=\frac{4\pi^{2}}{GM}a^{3}$ (1)

Where;

$G$ is the Gravitational Constant and its value is $6.674(10)^{-11}\frac{m^{3}}{kgs^{2}}$

$M=6.39(10)^{23}kg$ is the mass of Mars

$a=3.4(10)^{6}m$ is the semimajor axis of the orbit the spacecraft describes around Mars (assuming it is a <u>circular orbit </u>and a <u>low orbit near the surface </u>as well, the semimajor axis is equal to the radius of the orbit)

If we want to find the period, we have to express equation (1) as written below and substitute all the values:

$T=\sqrt{\frac{4\pi^{2}}{GM}a^{3}}$ (2)

$T=\sqrt{\frac{4\pi^{2}}{(6.674(10)^{-11}\frac{m^{3}}{kgs^{2}})(6.39(10)^{23}kg)}(3.4(10)^{6}m)^{3}}$ (3)

$T=\sqrt{11581157.44 s^{2}}$ (4)

Finally:

$T=3403.1099s=56.718min$ This is the orbital period of a spacecraft in a low orbit near the surface of mars

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3 years ago

What actions can be explained by physics?

Vesna [10]

Всяко действие има равно по големина и противоположно по посока противодействие.

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3 years ago

A century ago, swords were made from various metals, especially steel. The property that makes steel a good choice for sword mak

Nikolay [14]

The answer is a solid

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3 years ago

What is the definition of speed and the formula for calculation?

pashok25 [27]

For a body moving at a uniform velocity you can calculate the speed by dividing the distance traveled by the amount of time it took, for example one mile in 1/2 hour would give you 2 miles per hour. If the velocity is non-uniform all you can say is what the average speed is.

HOPE IT HELPS YOU

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3 years ago