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fiasKO [112]
2 years ago
15

What is the difference between center of mass and center of gravity?

Physics
2 answers:
sweet [91]2 years ago
5 0

Answer:

Centre of mass is the point at which the distribution of mass is equal in all directions, and does not depend on gravitational field. Centre of gravity is the point at which the distribution of weight is equal in all directions, and does depend on gravitational field.

sashaice [31]2 years ago
5 0

Answer:

Centre of mass is the point at which the distribution of mass is equal in all directions, and does not depend on gravitational field.

Centre of gravity is the point at which the distribution of weight is equal in all directions, and does depend on gravitational field.

hope this helps you ☺️☺️

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Oksanka [162]
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3 years ago
A box that has a mass of 80 kg slides down a ramp with a 30 degree angle. The free-body diagram shows the forces acting on the b
Mkey [24]

The force responsible for sliding the block down along the ramp is the component of the weight parallel to the ramp.

The weight of the block is

W=mg=(80 kg)(9.8 m/s^2)=784 N

The component of the weight parallel to the ramp is

W_{par} = W sin 30^{\circ}= (784 N)( sin 30^{\circ} )=392 N

And now we can find the acceleration of the box by using Newton's second law:

a=\frac{F}{m}=\frac{392 N}{80 kg}=4.9 m/s^2


So, the correct answer is

-4.9 m/s2

(the negative just means we have taken "upward along the ramp" as positive direction)

5 0
2 years ago
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What are the types of magnet​
KengaRu [80]

Answer: pls mark me as a brainliest friend pls, it would be great help for me

Explanation: There are three types of magnets: permanent magnets, temporary magnets, and electromagnets. Permanent magnets emit a magnetic field without the need for any external source of magnetism or electrical power.

Hope it’s useful friend…

Good luck and have a great day buddy…

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4 0
2 years ago
In Fig. 21-25, particle 1 of charge &1.0 mC and particle 2 of charge $3.0 mC are held at separation L ! 10.0 cm on an x axis
Kaylis [27]

Answer:

Since the particle 1 and 2 are on the x-axis, the 3rd particle should also be on the x-axis in order the net force on it to be zero.

Let's denote the distance between particles 1 and 3 as x. Therefore the distance between particles 2 and 3 is (0.1 - x), since the distance between 1 and 2 is 0.1 m.

Coulomb's Law states the force between charges as

F_{1-3} = \frac{1}{4\pi \epsilon_0}\frac{q_1q_3}{x^2}

F_{2-3} = \frac{1}{4\pi \epsilon_0}\frac{q_2 q_3}{(0.1 -x)^2}

The question asks that F_{1-3} = F_{2-3}, so

\frac{1}{4\pi \epsilon_0}\frac{1\times 10^{-3} \times q_3}{x^2} = \frac{1}{4\pi \epsilon_0}\frac{3\times 10^{-3}\times q_3}{(0.1 - x)^2}\\\frac{1}{x^2} = \frac{3}{(0.1 - x)^2}\\3x^2 = 0.01 -0.2x + x^2\\2x^2 + 0.2x - 0.01 = 0\\x_1 = 0.036m\\x_2 = -0.136m

We will take the positive root:

x = 0.036~m away from the first particle.

Explanation:

Since Fig. 21-25 is not given in the question, the exact locations are not known. However, the location of the third particle is found to be 0.036 m away from the first particle and the third particle is located between the particles 1 and 2.

8 0
2 years ago
Throwing a football is what type of energy
Finger [1]

Answer:

Chemical potential energy

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3 0
3 years ago
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