A baseball of mass 0.143 kg is thrown from the roof of a building 23.1 m above the ground. Its initial velocity is 37.6 m/s at a
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The kinetic energy of the mass at the instant it passes back through its equilibrium position is about 1.20 J
Let's recall Elastic Potential Energy formula as follows:
where:
<em>Ep = elastic potential energy ( J )</em>
<em>k = spring constant ( N/m )</em>
<em>x = spring extension ( compression ) ( m )</em>
Let us now tackle the problem!
<u>Given:</u>
mass of object = m = 1.25 kg
initial extension = x = 0.0275 m
final extension = x' = 0.0735 - 0.0275 = 0.0460 m
<u>Asked:</u>
kinetic energy = Ek = ?
<u>Solution:</u>
<em>Firstly , we will calculate the spring constant by using </em><em>Hooke's Law</em><em> as follows:</em>
<em>Next , we will use </em><em>Conservation of Energy</em><em> formula to solve this problem:</em>
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Grade: High School
Subject: Physics
Chapter: Elasticity
