Answer:
https://www.chegg.com/homework-help/questions-and-answers/part-20-cm-long-stick-m-0400-kg-lifted-rope-tied-70-cm-upper-end-end-touches-smooth-floor--q81268572
The electrostatic force between two charges Q1 and q is given by

where
ke is the Coulomb's constant
Q1 is the first charge
q is the second charge
r is the distance between the two charges
Re-arranging the formula, we have

and since we know the value of the force F, of the charge Q1 and the distance r between the two charges, we can calculate the value of q:

And since the force is attractive, the two charges must have opposite sign, so the charge q must have negative sign.
Your answer for this question is the third option.
Answer:
7.46 J/kg/K
Explanation:
The heat absorbed or lost is:
q = mCΔT
where m is the mass, C is the heat capacity, and ΔT is the change in temperature.
Given q = 15.0 J, m = 0.201 kg, and ΔT = 10.0 °C:
15.0 J = (0.201 kg) C (10.0 °C)
C = 7.46 J/kg/°C
Which is the same as 7.46 J/kg/K.
When red light illuminates a grating with 7000 lines per centimeter, its second maximum is at 62.4°. What is the wavelength of this light?
ans: 633nm