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Reika [66]
3 years ago
6

Two objects are dropped from a bridge an interval of 1.0s apart. Air resistance is negligible. During the time that both objects

continue to fall, their separation increases.
Can someone explain why it increases, instead of staying constant?
Physics
1 answer:
inysia [295]3 years ago
5 0
Their separation would be constant if they were both falling at the same speed. But they're not. A falling object falls 9.8 m/s faster every second than it fell in the previous second.

So the one that dropped first ... and had an extra second to fall ... is always falling faster than the one that dropped later. So it keeps getting farther ahead.
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<u>Answer</u>

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Metal A will transfer heat to the water since it's temperature is higher than that of water.

Metal B will also transfer heat to the water since it's temperature is higher than that of water.

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Metal D will also get heat from the water since it is colder than water.

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Sergio039 [100]

Answer:

The net power needed to change the speed of the vehicle is 275,000 W

Explanation:

Given;

mass of the sport vehicle, m = 1600 kg

initial velocity of the vehicle, u = 15 m/s

final velocity of the vehicle, v = 40 m/s

time of motion, t = 4 s

The force needed to change the speed of the sport vehicle;

F = \frac{m(v-u)}{t} \\\\F = \frac{1600(40-15)}{4} \\\\F = 10,000 \ N

The net power needed to change the speed of the vehicle is calculated as;

P_{net} = \frac{1}{2} F[u + v]\\\\P_{net} = \frac{1}{2} \times 10,000[15 + 40]\\\\P_{net} = 275,000 \ W

3 0
3 years ago
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solniwko [45]

Answer:

It is b

Explanation:

The question tells you that the distance was increased 3 times the original distance, which means it was moved 3 times

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