Question

Calculate the amount of torque of an object being pushed by 6 N force along a circular path of a radius of 1x10^-2 mat 30 degree angle.

Answer 1

Answer:

The amount of torque is 0.03 N.m.

Explanation:

To find the amount of torque we need to use the following equation:

$\tau = \vec {r} \times \vec{F} = rFsin(\theta)$   (1)

Where:

r: is the radius = 1x10⁻² m

F: is the force = 6 N

θ: is the angle = 30°

By entering the above values into equation (1) we have:

$\tau = 1 \cdot 10^{-2} m*6 N*sin(30) = 0.03 N.m$  

Therefore, the amount of torque is 0.03 N.m.

I hope it helps you!