Answer:
The magnitude of minimum potential difference is 1800 V
Explanation:
Given:
Electric field 
Gap between electrodes 
m
For finding the minimum potential difference,
V
Therefore, the magnitude of minimum potential difference is 1800 V
Answer:
Here's the Density Formula: D = M/V
Q: How does mass affect density?
A: <em>Mass is a factor in density, the density is proportional to the mass. So as the mass increases, so does the density, provided the volume remains constant.</em>
Q: How does volume affect density?
A:<em> If an object has a larger mass than its volume it has a high density, if an object has a smaller mass than its volume it has a lower density.</em>
Explanation:
<em><u>I really Hope this Helps!!</u></em>
Explanation:
'gerfe4egd4gwdrferdfw14589u99y999q EP and it's not the same thing to say about this is a good day for the next few weeks of age or something else I would have to do it for you and your friends to be the first to see the new album and I am a big deal to the world is not the same thing to say about this one for you and I am a big deal to me that he was the first to see you in a few years back and forth to see the world is not a fan and a few years back and I have to be the best way possible for the next few days later and the other side is the only thing that you can get it right here is the only thing I can get it right here is a great time to get a free download of my life
Answer:
39.81 N
Explanation:
I attached an image of the free body diagrams I drew of crate #1 and #2.
Using these diagram, we can set up a system of equations for the sum of forces in the x and y direction.
∑Fₓ = maₓ
∑Fᵧ = maᵧ
Let's start with the free body diagram for crate #2. Let's set the positive direction on top and the negative direction on the bottom. We can see that the forces acting on crate #2 are in the y-direction, so let's use Newton's 2nd Law to write this equation:
- ∑Fᵧ = maᵧ
- T₁ - m₂g = m₂aᵧ
Note that the tension and acceleration are constant throughout the system since the string has a negligible mass. Therefore, we don't really need to write the subscripts under T and a, but I am doing so just so there is no confusion.
Let's solve for T in the equation...
- T₁ = m₂aᵧ + m₂g
- T₁ = m₂(a + g)
We'll come back to this equation later. Now let's go to the free body diagram for crate #1.
We want to solve for the forces in the x-direction now. Let's set the leftwards direction to be positive and the rightwards direction to be negative.
The normal force is equal to the x-component of the force of gravity.
- (F_n · μ_k) - m₁g sinΘ = m₁aₓ
- (F_g cosΘ · μ_k) - m₁g sinΘ = m₁aₓ
- [m₁g cos(30) · 0.28] - [m₁g sin(30)] = m₁aₓ
- [(6)(9.8)cos(30) · 0.28] - [(6)(9.8)sin(30)] = (6)aₓ
- [2.539595871] - [-58.0962595] = 6aₓ
- 60.63585537 = 6aₓ
- aₓ = 10.1059759 m/s²
Now let's go back to this equation:
We have 3 known variables and we can solve for the tension force.
- T = 2(10.1059759 + 9.8)
- T = 2(19.9059759)
- T = 39.8119518 N
The tension force is the same throughout the string, therefore, the tension in the string connecting M2 and M3 is 39.81 N.
The gravitational attraction between two planets is 4905.95 N
<h3>What is gravitational attraction?</h3>
When two objects with masses are placed at a distance, there will an attractive force acting between them.
According to the Newton's law of gravitation, gravitational force is
F = Gm₁m₂ /r²
where r is the distance between the masses m₁ and m₂ and G is the gravitational constant G = 6.67 x 10⁻¹¹ N-m²/kg²
Substitute the values into the expression, we get
F = 6.67 x 10⁻¹¹ x 2.25 x 10²⁰ x 6.20 x 10¹⁸ / (435,500 x 1000)²
F= 4905.95 N
Thus, the gravitational attraction between two planets is 4905.95 N.
Learn more about gravitational attraction.
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