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Rina8888 [55]
3 years ago
8

Cuales son las del ciclo de el fósforo

Chemistry
1 answer:
ziro4ka [17]3 years ago
4 0

Answer:

El ciclo del fósforo es un ciclo biogeoquímico que describe el movimiento de este elemento químico en un ecosistema. Los seres vivos toman el fósforo en forma de fosfatos a partir de las rocas fosfatadas, que mediante meteorización se descomponen y liberan los fosfatos.

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Calculate the Equilibrium constant Kc at 25 C from the free - energy change for the following reaction . Zn(s) + 2Ag+(aq)<---
FinnZ [79.3K]

Answer:  Kc=1.24*10^5^2

Explanation: For the given reaction:

Kc=\frac{[Zn^+^2]}{[Ag^+]^2}

Concentrations of the ions are not given so we need to think about another way to calculate Kc.

We can calculate the free energy change using the standard cell potential as:

\Delta G^0=-nFE^0_c_e_l_l

E^0_c_e_l_l can be calculated using standard reduction potentials.

Standard reduction potential for zinc is -0.76 V and for silver, it is +0.78 V.

E^0_c_e_l_l = E^0_c_a_t_h_o_d_e+E^0_a_n_o_d_e

Reduction takes place at anode and oxidation at cathode. As silver is reduced, it is cathode. Zinc is oxidized and so it is anode.

E^0_c_e_l_l  = 0.78 V - (-0.76 V)

E^0_c_e_l_l  = 0.78 V + 0.76 V

E^0_c_e_l_l  = 1.54 V

Value of n is two as two moles of electrons are transferred in the cell reaction F is Faraday constant and its value is 96485 C/mol of electron .

\Delta G^0=-(2*96485*1.54)

\Delta G^0 = -297173.8 J

Now we can calculate Kc using the formula:

\Delta G^0=-RTlnKc

T = 25+273 = 298 K

R = 8.314JK^-^1mol^-^1

--297173.8 = -(8.314*298)lnKc

297173.8 = 2477.572*lnKc

lnKc=\frac{297173.8}{2477.572}

lnKc = 119.946

Kc=e^1^1^9^.^9^4^6

Kc=1.24*10^5^2

5 0
3 years ago
Each of the following names is wrong. Draw structures based on them, and correct the names:(b) 1,1,1-trimethylheptane
devlian [24]

The correct IUPAC name of 1,1,1-trimethylheptane is 2,2-dimethyloctane.

<h3>IUPAC NAME:</h3>

It is systematic way of nomenclature of organic compounds.

It is based on the position of functional groups, preference of the functional group, long or short chain of carbon, preference of double bond, single and triple bond, branching of carbon chain, etc.

The given compound is 1,1,1-trimethylheptane.

The given name is wrong according to IUPAC name because the numbering of carbon atom should be done in that way in which the carbon atom chain is largest.

Here, in this case the numbering is done from right side. Thus the largest carbon chain have 8 carbon atom.

If the numbering is done according to the question, number of carbon atom in straight chain is 7.

Thus, we concluded that the Correct IUPAC name of 1,1,1-trimethylheptane is 2,2-dimethyloctane.

learn more about Nomenclature:

brainly.com/question/14094007

#SPJ4

5 0
2 years ago
A car moving at 12 m/s applies its brakes and comes to a stop in 2 s. What was its acceleration?​
vredina [299]

Answer:

<h2>6 m/s²</h2>

Explanation:

The acceleration of an object given it's velocity and time taken can be found by using the formula

a =  \frac{v}{t}  \\

where

a is the acceleration

v is the velocity

t is the time

From the question we have

a =  \frac{12}{2}  \\

We have the final answer as

<h3>6 m/s²</h3>

Hope this helps you

8 0
3 years ago
The prefix mili-means a thousand
OLEGan [10]
<h2>Answer:</h2>

<em>Given data:</em>

1 kilogram = 1,000 grams

how many kilograms is 1,216 grams?

<em>Solution:</em>

1000 grams = 1 kilogram

1 gram = 1/1000 kilograms

1216 grams = 1/1000 * 1216 = 1.216 kilograms.

                                                    <em> Hence 1216 grams =  1.216 kilograms.</em>

3 0
3 years ago
The gravitational pull of the Moon has the greatest influence on the water levels of Earth’s ocean tides. If the distance betwee
kherson [118]
The water levels would lower, because as the moon gets farther away, it's gravitational pull decreases. Hope this helps! :)
6 0
3 years ago
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