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murzikaleks [220]
3 years ago
11

If the position of a particle on the x-axis at time t is −5t2, then the average velocity of the particle for 0 ≤ t ≤ 3 is

Physics
1 answer:
Drupady [299]3 years ago
3 0

Answer:

v = 15 m / s

Explanation:

In this exercise we are given the position function

          x = 5 t²

and we are asked for the average velocity in an interval between t = 0 and t= 3 s, which is defined by the displacement between the time interval

          v= \frac{v_{f} - v_{o} }{t_{f} - t_{o} }

let's look for the displacements

        t = 0     x₀ = 0 m

        t = 3     x_{f} = 5 3 2

                     x_{f} = 45 m

 

we substitute

           v = \frac{45 -0}{3 - 0}

           v = 15 m / s

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Answer:

No

Explanation:

Not all metals stick to magnets. Like aluminum. if you were to stick a magnet on to an aluminum it would fall off.

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two boxes sit on a frictionless surface and are in contact with one another. the first box has a mass of 7 kg and the second box
egoroff_w [7]
The acceleration of the boxes depends on the mass and weight. 

we have a mass of 7 and 8 kilograms

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It will leave you with 100 N. 

finally take the sq rt of 100 to get 10
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To maintain your body temperature your body converts chemical potential energy into thermal energy true or false
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Falls resulting in hip fractures are a major cause of injury and even death to the elderly. Typically, the hip’s speed at impact
Westkost [7]

Answer:

-5.8868501529 m/s² or -5.8868501529g

0.118909090909 s

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration

g = Acceleration due to gravity = 9.81 m/s²

v^2-u^2=2as\\\Rightarrow a=\dfrac{v^2-u^2}{2s}\\\Rightarrow a=\dfrac{1.3^2-2^2}{2\times 0.02}\\\Rightarrow a=-5.8868501529\ m/s^2

Dividing by g

\dfrac{a}{g}=\dfrac{-57.75}{9.81}\\\Rightarrow a=-5.8868501529g

The acceleration is -5.8868501529 m/s² or -5.8868501529g

v=u+at\\\Rightarrow t=\dfrac{v-u}{a}\\\Rightarrow t=\dfrac{1.3-2}{-5.8868501529}\\\Rightarrow t=0.118909090909\ s

The time taken is 0.118909090909 s

7 0
3 years ago
A system gains 1500 J of heat, while the internal energy of the system increases by 4500 J and the volume decreases by . Assume
Assoli18 [71]

Answer:

Hence the pressure is 3\times 10^5 Pa

Explanation:

Given data

Q=1500 J   system gains heat

ΔV=- 0.010 m^3     there is a decrease in volume

ΔU= 4500 J        internal energy decrease

We know work done is

W= Q- ΔU

=1500-4500= -3000 J

The change in the volume at constant pressure is

ΔV= W/P

there fore P = W/ΔV= -3000/-0.01= 3×10^5

Hence the pressure is 3\times 10^5 Pa

3 0
3 years ago
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