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2 years ago

In Hooke's law, Fspring=kΔx , what does the Fspring stand for?

Physics

2 answers:

Mrrafil [7]2 years ago

6 0

Answer:

The amount of force acting on the spring.

Explanation:

Here, Fspring= kΔx is a equation denoting the amount of force acting on the spring.

where, k = spring constant.

Δx= change in the length of the spring.

so, for every Δx change in spring length, kΔx force acts on the spring.

Agata [3.3K]2 years ago

6 0

Answer:

The amount of force acting on the spring.

Explanation:

Here,

Fspring= kΔx is a equation denoting the amount of force acting on the spring.

where, k = spring constant.

Δx= change in the length of the spring.

so, for every Δx change in spring length, kΔx force acts on the spring.

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A farsighted boy has a near point at 2.3 m and requires eyeglasses to correct his vision. Corrective lenses are available in inc

tino4ka555 [31]

Answer:

P = 3.5 D

Explanation:

As we know that convex lens is to be used to make the near point of eye to be correct

So we will have

$\frac{1}{d_i} + \frac{1}{d_o} = \frac{1}{f}$

here we have

$d_i = 2.3 m = 230 cm$

$d_o = 25 cm$

now plug in all values into the formula

$-\frac{1}{230} + \frac{1}{25} = \frac{1}{f}$

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2 years ago

What term best describes the regular path of a spacecraft or other object around a planetary body?

Law Incorporation [45]

B. Orbit. The planets orbit the sun, the moon orbits earth, etc.

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2 years ago

or Ethernet, if an adapter determines that a frame it has just received is addressed to a different adapter it discards the fram

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For Ethernet, if an adapter determines that a frame it has just received is addressed to a different adapter

a. it discards the frame without sending an error message to the network layer

b. it sends a NACK (not acknowledged frame) to the sending host

c. it delivers the frame to the network layer, and lets the network layer decide what to do

d. it discards the frame and sends an error message to the network layer

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Option A

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3 years ago

Two balls of equal mass are thrown horizontally with the same initial velocity. They hit identical stationary boxes resting on a

11111nata11111 [884]

Answer:

The box 1 moves faster.

Explanation:

lets

Mass =m kg

Initial velocity = u m/s

Initial velocity of box = 0 m/s

Let stake mass of block = m

When ball bounces back:

The final speed of the box = v

Final speed of ball = - u

Pi = Pf ( From linear momentum conservation)

m x u + m x 0 = m ( - u) + m v

mu + mu = m v

v= 2 u

When ball get stuck :

The final speed of ball and box = v

Pi = Pf ( From linear momentum conservation)

m x u + m x 0 = (m+m) v

v= u /2

So the box 1 moves faster.

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3 years ago