Answer:
C
Step-by-step explanation:
V=4
/3πr3
3000=1 1/3*3.14*r*r*r
3000=4.18666667*r*r*r
716.560509=
Cube root the number
8.94851471456=r
TSA=4
TSA=4*3.14*8.94851471456*8.94851471456
TSA=1006.26
Since we used different numbers for pi and I rounded our answer will be different but the answer is C
Multiply the quantity in ounces (including the unit) by the fraction
(1 pint) / (16 fl oz) .
Answer:
It is p = 1
Step-by-step explanation:
p⁰=1 because it is basically saying and when simplifying fractional exponents we can flip the bottom exponent up to the top if we change the sign, leaving us with : (p⁵-p⁵)=p⁰
Answer:
The slope is -3/4 and the y-intercept is 1.
Step-by-step explanation:
B is the point where the line cross the y-axis, or vertical axis. Slope is the steepness of the line. Determined by rise over run. When the slope goes down 3 units, the slope goes to the right 4 units.
Answer:
P(cell has at least one of the positive nickel-charged options) = 0.83.
P(a cell is not composed of a positive nickel charge greater than +3) = 0.85.
Step-by-step explanation:
It is given that the Nickel Charge Proportions found in the battery are:
0 ==> 0.17
.
+2 ==> 0.35
.
+3 ==> 0.33
.
+4 ==> 0.15.
The numbers associated to the charge are actually the probabilities of the charges because nickel is an element that has multiple oxidation states that is usually found in the above mentioned states.
a) P(cell has at least one of the positive nickel-charged options) = P(a cell has +2 nickel-charged options) + P(a cell has +3 nickel-charged options) + P(a cell has +4 nickel-charged options) = 0.35 + 0.33 + 0.15 = 0.83.
Or:
P(a cell has at least one of the positive nickel-charged options) = 1 - P(a cell has 0 nickel-charged options) = 1 - 0.17 = 0.83.
b) P(a cell is not composed of a positive nickel charge greater than +3) = 1 - P(a cell is composed of a positive nickel charge greater than +3)
= 1 - P(a cell has +4 nickel-charged options) '.' because +4 is only positive nickel charge greater than +3
= 1 - 0.15
= 0.85
To summarize:
P(cell has at least one of the positive nickel-charged options) = 0.83!!!
P(a cell is not composed of a positive nickel charge greater than +3) = 0.85!!!
