Let f(x) = x^2 – 81. Find f–1(x). Can someone double-check what I have?

Mathematics

2 answers:

Trava [24]3 years ago

5 0

I hope this helps you

y=x^2-81

x^2=y+81

x=square root of y+81

f^-1 (x)= square root of x+81

Stella [2.4K]3 years ago

5 0

<span>For the answer to the question above, if you are just checking your answer, I'll just show the solution. Is it just ok?
f(x) = x2 - 81
y = x^2 - 81
x = y^2 - 81
x + 81 = y^2
y = ± √(x + 81)

f⁻¹(x) = ± √(x + 81) answer

Answer is ±√x+81

I hope I helped you with my answer somehow.</span><span>
</span>

You might be interested in

2(x+4)+4x<br><br>simplify expression

OLEGan [10]

Answer:

6x+8

Step-by-step explanation:

2(x+4)+4x

2x+8+4x

6x+8

4 0

2 years ago

Select either relation (if the set is a relation but not a function), function (if the set is both a relation and a function), o

galina1969 [7]

Answer: The correct options are

(A) relation

(B) function.

Step-by-step explanation: We are given to check whether the following set is a relation or a relation and a function or neither :

A = {(1, 2) (2, 2) (3, 2) (4, 2)} .

Let us consider the following two sets :

U = {1, 2, 3, 4} and V = {2}.

Then, we see that the Cartesian Product of U and V is given by

U × V = {(1, 2) (2, 2) (3, 2) (4, 2)}.

Since a relation is a subset of Cartesian product, so the given set A is a relation.

Also, we know that a relation is a function if every first element is associated with one second element.

Since the relation A satisfies this condition, so the relation A is a function.

Thus, the given set A is both a relation and a function.

Option (A) and (B) are correct.

6 0

2 years ago

Given f (x) = 1/4x-3/4<br> Find f^-1

Snowcat [4.5K]

The inverse of a function f(x) is f⁻¹(x) = 4x + 3 after using the concept of the inverse of a function.

<h3>What is a function?</h3>

It is defined as a special type of relationship, and they have a predefined domain and range according to the function every value in the domain is related to exactly one value in the range.

We have a function:

$\rm f(x) = \dfrac{1}{4}x-\dfrac{3}{4}$