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Llana [10]
3 years ago
13

On what three factors the rise in the temperature of a body on heating depends?​

Physics
2 answers:
grin007 [14]3 years ago
3 0

Answer:

The mass of the body, The rise, and the temperature I think!

Explanation:

Andrews [41]3 years ago
3 0

Answer:

The mass of the body

The rise or fall in the temperature of the body

Nature of the material of the body.

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A sound wave in air has a frequency of 354 Hz and travels with a speed of 343 m/s. How far apart are the wave crests in meters.
dsp73

Given :

The frequency of travelling sound = f = 282 Hz

The speed of travelling sound = c = 343 m/s

To Find :

The distance of waves crests

Solution :

∵ wavelength of sound wave =

i.e         =

Or,        =

∴          = 1.12   m

So, The wavelength of sound wave =   = 1.21  m

Thus , The distance of waves crests =wavelength of sound wave = 1.21 m

Hence, The distance of waves crests is 1.21 meters    Answer

6 0
3 years ago
A stone tied to the end of a string is swung with a constant speed around a horizontal circle with a radius of 1.5m. It makes tw
Firdavs [7]
In order to answer this question, you need to complete this formula :

a = r. w^2

a = 1.5 [(4). (3.14)] ^2 

= 236.6304 m^2

Hope this helps

6 0
3 years ago
What is an<br> example of a force?<br> Pressure<br> Power<br> Energy<br> Weight
Kryger [21]

Answer:

weight

Explanation:

weight is the pull of gravity so its a force !!

5 0
3 years ago
An electron moves in a circular path perpendicular to a magnetic field of magnitude 0.285 T. If the kinetic energy of the electr
Elis [28]

Answer:

The speed of the electron is 6.79 x 10⁵ m/s

The radius of the circular path is 1.357 x 10⁻⁵ m

Explanation:

Given;

magnetic field, B = 0.285 T

energy of electron, E = 2.10 x 10⁻¹⁹ J

The kinetic energy of the electron is calculated as;

K.E = \frac{1}{2} m_eV^2

Where;

m_e is the mass of electron = 9.11 x 10⁻³¹ kg

V is the speed of the electron

K.E = \frac{1}{2} m_eV^2\\\\V^2 = \frac{2.K.E}{m_e} \\\\V = \sqrt{\frac{2K.E}{m_e} } \\\\V = \sqrt{\frac{2*(2.1*10^{-19})}{9.11*10^{-31}} }\\\\V = 6.79 *10^{5} \ m/s

The radius of the circular path is given by;

R = \frac{M_eV}{qB}

where;

q is the charge of the electron = 1.6 x 10⁻¹⁹ C

R = \frac{M_eV}{qB} \\\\R = \frac{9.11 *10^{-31}*6.79 *10^{5}}{1.6*10^{-19}*0.285} \\\\R = 1.357 *10^{-5} \ m

8 0
3 years ago
A sailboat moves north for a distance of 10.00 km when blown by a wind from the exact south with a force of 5.00 x 10^4 N.
STatiana [176]

Answer:

5*10^8Nm

Explanation:

work done= displacement* force

Since the wind blows in the direction that the boats want to travel, all values would be positive.

10*10^3*(5*10^4)=5.00*10^8Nm

5 0
3 years ago
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