The distance travelled during the given time can be found out by using the equations of motion.
The distance traveled during the time interval is "13810.8 m".
First, we will find the deceleration of the motorcycle by using the first <em>equation of motion</em>:

where,
vi = initial velocity = (518 km/h)
= 143.89 m/s
vf = final veocity = 60 % of 143.89 m/s = (0.6)(143.89 m/s) = 86.33 m/s
a = deceleration = ?
t =time interval = 2 min = 120 s
Therefore,

a = -0.48 m/s²
Now, we will use the second <em>equation of motion </em>to find out the distance traveled (s):

<u>s = 13810.8 m = 13.81 km</u>
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Learn more about the equations of motion here:
brainly.com/question/20594939?referrer=searchResults
The attached picture shows the equations of motion.
Troposphere, stratosphere, mesosphere, thermosphere, exosphere
Answer:
See below
Explanation:
Vertical position is given by
df = do + vo t - 1/2 a t^2 df = final position = 0 (on the ground)
do =original position = 2 m
vo = original <u>VERTICAL</u> velocity = 0
a = acceleration of gravity = 9.81 m/s^2
THIS BECOMES
0 = 2 + 0 * t - 1/2 ( 9.81)t^2
to show t =<u> .639 seconds to hit the ground </u>
During this .639 seconds it flies horizontally at 10 m/s for a distance of
10 m/s * .639 s =<u> 6.39 m </u>
Answer: R = 394.36ohm
Explanation: In a LR circuit, voltage for a resistor in function of time is given by:

ε is emf
L is indutance of inductor
R is resistance of resistor
After 4s, emf = 0.8*19, so:





R = 394.36
In this LR circuit, the resistance of the resistor is 394.36ohms.