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pav-90 [236]
4 years ago
11

boiling point density conductivity color These may all be classified as the ______________ of a substance. A) nuclear properties

B) physical properties C) chemical properties D) reactive properties
Chemistry
2 answers:
maria [59]4 years ago
3 0
Observing the choices i suppose it could be D because boiling is a reaction 
Vinil7 [7]4 years ago
3 0
The answer would actually be B.

Those properties would certainly not be the nuclear properties, since those are given at the smallest value (electrons, particles, polarity, etc.) so it isn't A.

While it <em>would</em> be possible for C to be the answer, conductivity and density debunk that. Chemical properties are properties of matter that pertain to only <em>chemical reactions</em>.

And saving the best for last, D is actually just impossible. In the English language, reactive properties may be a proper phrase. But in science, there is only such a thing as <em>reactivity</em>. There are no such things as reactive properties.

Even if my explanations for incorrectness are wrong; my thesis for why B is correct is because, color is a physical property, the boiling point is a physical property, conductivity is a physical property.

Let me know if I'm wrong! :D
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What is the percent by mass of water in Na S04.10H20?
dalvyx [7]

Answer:

                    Percent by mass of water is 56%

Explanation:

                    First of all calculate the mass of hydrated compound as,

Mass of Sodium = Na × 2 = 22.99 × 1 = 45.98 g

Mass of Sulfur = S × 1 = 32.06 × 1 = 32.06 g

Mass of Oxygen = O × 14 = 16 × 14 = 224 g

Mass of Hydrogen = H × 20 = 1.01 × 20 = 20.2 g

Mass of Na₂S0₄.10H₂O = 322.24 g

Secondly, calculate mass of water present in hydrated compound. For this one should look for the coefficient present before H₂O in molecular formula of hydrated compound. In this case the coefficient is 10, so the mass of water is...

Mass of water = 10 × 18.02

Mass of water = 180.2 g

Now, we will apply following formula to find percent of water in hydrated compound,

           %H₂O  =  Mass of H₂O / Mass of Hydrated Compound × 100

Putting values,

                                      %H₂O  = 180.2 g / 322.24 g × 100

                                           %H₂O =  55.92 % ≈ 56%

3 0
3 years ago
Help with 5b. Full explanation please
larisa86 [58]
Not elementary school work
8 0
4 years ago
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