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3 years ago

12. You are building a go-cart. You want to know how you can make it go as fast as it can.

Physics

1 answer:

atroni [7]3 years ago

4 0

Answer:

Physical measures: Reduction of internal friction, high static friction tire system

chemist. : air-fuel ratio as efficient

Explanation:

A go-Kart is a vehicle that can be with a motor or with pedals, which is in contact with the ground.

Physical measures that help increase vehicle speed are:

* Reduction of internal friction, use bearings, with greased joints to reduce friction

* Decreased friction when forward creating an aerodynamic raindrop shape, sharp at the front and with a rapid descent at the rear, but without abrupt cuts to the geometry

* Path difference for air passing through the top and bottom, to create a downward force help lower the car by increasing speed

* A high static friction tire system so you can move faster on surfaces and take turns faster

* A shifting system to have an effective torque either pedal or motor, gear shifting system

From the point of chemist.

* Obtain an air-fuel ratio as efficient as possible to increase the force per unit of fuel.

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Which statement best describes the movement of atoms in a solid?

Helga [31]

Answer:

They have no freedom to move

Explanation:

Particles can be solids, liquids and gases.

Solids are the substances in which the atoms are very close to each other. It is very difficult to separate the molecules. The atoms cannot move from one place to another. The inter molecular forces between them is very strong.

Hence, the correct option that describes the movement of atoms in a solid is (c) "They have no freedom to move".

5 0

4 years ago

When a liquid is introduced into the air space between the lens and the plate in a Newton's-rings apparatus, the diameter of the

Leviafan [203]

Answer:

$n_l=1.58$

Explanation:

Newton's ring equation relates the initial and final diameter of the ring, to the index of refraction of the air and the index of refraction of the liquid between the lens and the plates, as follows:

$n_ld_f^2=n_ad_i^2$

Solving for :

$n_l=n_a\frac{d_i^2}{d_f^2}\\$

Recall that the refractive index of the air is 1. So, replacing the given diameters:

$n_l=\frac{(1.52cm)^2}{(1.21cm)^2}\\\\n_l=1.58$

3 0

4 years ago

A piano tuner stretches a steel piano wire with a tension of 1070 N . The wire is 0.400 m long and has a mass of 4.00 g . A. Wha

pychu [463]

A. 409 Hz

The fundamental frequency of a string is given by:

$f_1=\frac{1}{2L}\sqrt{\frac{T}{m/L}}$

where

L is the length of the wire

T is the tension in the wire

m is the mass of the wire

For the piano wire in this problem,

L = 0.400 m

T = 1070 N

m = 4.00 g = 0.004 kg

So the fundamental frequency is

$f_1=\frac{1}{2(0.400)}\sqrt{\frac{1070}{(0.004)/(0.400)}}=409 Hz$

B. 24

For this part, we need to analyze the different harmonics of the piano wire. The nth-harmonic of a string is given by

$f_n = nf_1$

where $f_1$ is the fundamental frequency.

Here in this case

$f_1 = 409 Hz$

A person is capable to hear frequencies up to

$f = 1.00 \cdot 10^4 Hz$

So the highest harmonics that can be heard by a human can be found as follows:

$f=nf_1\\n= \frac{f}{f_1}=\frac{1.00\cdot 10^4}{409}=24.5 \sim 24$

8 0

4 years ago

What is the ratio of the gravitational pull of the sun on the moon to that of the earth on the moon? (assume the distance of the

professor190 [17]

Acceleration of Gravity Sun-Moon System

G = 6.67260E-11 m^3/(kg sec^2)
m1 = mass of Sun = 1.989E+30 kg
m2 = mass of Moon = 7.3476E+22 kg
r = distance between Sun and Moon = distance between Sun and Earth - distance between Earth and Moon = 149,600,000 km - 384,400 km

<span>g = 0.00596 m/s^2</span>

5 0

3 years ago

Which of these forces pull or push upward, and which pull or push downward? Explain.

PtichkaEL [24]

Answer:

A force is a push or pull that acts upon an object as a result of that objects interactions

Explanation:

8 0

4 years ago